Driver class CarInLine: import java.io.*; class CarInLine{ static int ctr=0; static int cars,cash; static int DepartureTime=0; static int arrivalTime=0; static int ctr_tax=0; CarInLine(){ ctr++; cars=0; cash=0; } void pcar(){ System.out.print(“\nEnter the amount of toll:”); cash=cash+cash; cars++; } void npcar(){ cars++; } void disp(){ System.out.print(” \n\Number of cashiers\n\n”); System.out.print(“\tAverage time\n\n”); System.out.print(“\Optimum number of cashiers is"); } } void tax(int a){ if(a==1) ctr_tax++; } } class booth{ public static void main(String arg[]){ DataInputStream ins=new DataInputStream(System.in); int ans=1,ncar=5; do{ CarInLine c=new car(); try{ System.out.print("Press 1 if u want to pay tax "); ans=Integer.parseInt(ins.readLine()); c.tax(ans); System.out.print("Another car? Press 5 "); ncar=Integer.parseInt(ins.readLine()); } catch(IOException e){ } } while(ncar==5); System.out.println("Average Procesing time: "+car.ctr); int non = car.ctr - car.ctr_tax; System.out.println("No. of cars which have not paid tax: "+non); int amt = car.ctr_tax*50; System.out.println("Amount of cash collected: "+amt); } } Define ten queues, simulating the functionality of the process, increasing the number of cashiers from one, and collecting the average waiting time for each scenario. Each simulation will work with the same number of cars, which is considered 100. The maximum number of cashiers/toll booths is 10. Create the queue with link-based implementation. Create each queue with the corresponding number of cashiers, from 1 to 10, and record the average processing time. Save the processing time in an array of integer values representing the processing time. At the end of the simulation, display the results in a table with the number of cashiers and the average waiting time, measured in seconds. Choose the optimum number of cashiers, considering that the desired wait time is 1.5 minutes (90 seconds) Display the result of your simulation, which is the optimum number of cashiers. If you implement all the required methods correctly, the driver program should generate outputs similar to the following

Driver class CarInLine: import java.io.; class CarInLine{ static int ctr=0; static int cars,cash; static int DepartureTime=0; static int arrivalTime=0; static int ctr_tax=0; CarInLine(){ ctr++; cars=0; cash=0; } void pcar(){ System.out.print(“\nEnter the amount of toll:”); cash=cash+cash; cars++; } void npcar(){ cars++; } void disp(){ System.out.print(” \n\Number of cashiers\n\n”); System.out.print(“\tAverage time\n\n”); System.out.print(“\Optimum number of cashiers is"); } } void tax(int a){ if(a==1) ctr_tax++; } } class booth{ public static void main(String arg[]){ DataInputStream ins=new DataInputStream(System.in); int ans=1,ncar=5; do{ CarInLine c=new car(); try{ System.out.print("Press 1 if u want to pay tax "); ans=Integer.parseInt(ins.readLine()); c.tax(ans); System.out.print("Another car? Press 5 "); ncar=Integer.parseInt(ins.readLine()); } catch(IOException e){ } } while(ncar==5); System.out.println("Average Procesing time: "+car.ctr); int non = car.ctr - car.ctr_tax; System.out.println("No. of cars which have not paid tax: "+non); int amt = car.ctr_tax50; System.out.println("Amount of cash collected: "+amt); } } Define ten queues, simulating the functionality of the process, increasing the number of cashiers from one, and collecting the average waiting time for each scenario. Each simulation will work with the same number of cars, which is considered 100. The maximum number of cashiers/toll booths is 10. Create the queue with link-based implementation. Create each queue with the corresponding number of cashiers, from 1 to 10, and record the average processing time. Save the processing time in an array of integer values representing the processing time. At the end of the simulation, display the results in a table with the number of cashiers and the average waiting time, measured in seconds. Choose the optimum number of cashiers, considering that the desired wait time is 1.5 minutes (90 seconds) Display the result of your simulation, which is the optimum number of cashiers. If you implement all the required methods correctly, the driver program should generate outputs similar to the following

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Written in java,

Your Tasks:

Driver class CarInLine:
- import java.io.*;
  class CarInLine{
  static int ctr=0;
  static int cars,cash;
  static int DepartureTime=0;
  static int arrivalTime=0;
  static int ctr_tax=0;
  CarInLine(){
  ctr++;
  cars=0;
  cash=0;
  }
  void pcar(){
  System.out.print(“\nEnter the amount of toll:”);
  cash=cash+cash;
  cars++;
  }
  void npcar(){
  cars++;
  }
  void disp(){
  System.out.print(” \n\Number of cashiers\n\n”);
  System.out.print(“\tAverage time\n\n”);
  System.out.print(“\Optimum number of cashiers is");
  }
  }
  void tax(int a){
  if(a==1)
  ctr_tax++;
  }
  }
  class booth{
  public static void main(String arg[]){
  DataInputStream ins=new DataInputStream(System.in);
  int ans=1,ncar=5;
  do{
  CarInLine c=new car();
  try{
  System.out.print("Press 1 if u want to pay tax ");
  ans=Integer.parseInt(ins.readLine());
  c.tax(ans);
  System.out.print("Another car? Press 5 ");
  ncar=Integer.parseInt(ins.readLine());
  }
  catch(IOException e){
  }
  }
  while(ncar==5);
  System.out.println("Average Procesing time: "+car.ctr);
  int non = car.ctr - car.ctr_tax;
  System.out.println("No. of cars which have not paid tax: "+non);
  int amt = car.ctr_tax*50;
  System.out.println("Amount of cash collected: "+amt);
  }
  }
Define ten queues, simulating the functionality of the process, increasing the number of cashiers from one, and collecting the average waiting time for each scenario.
Each simulation will work with the same number of cars, which is considered 100.
The maximum number of cashiers/toll booths is 10.
Create the queue with link-based implementation.
Create each queue with the corresponding number of cashiers, from 1 to 10, and record the average processing time.
Save the processing time in an array of integer values representing the processing time.
At the end of the simulation, display the results in a table with the number of cashiers and the average waiting time, measured in seconds.
Choose the optimum number of cashiers, considering that the desired wait time is 1.5 minutes (90 seconds)
Display the result of your simulation, which is the optimum number of cashiers.
If you implement all the required methods correctly, the driver program should generate outputs similar to the following:

Number of cashiers:
Average time:
Optimum number of cashiers is: 9
Average processing time: 90
Press any key to continue..
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