Draw the principle organic product of the reaction. Be sure to include lone pairs and formal charges on structures, and include stereochemistry if relevant.
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- Draw the major product of this reaction. Ignore inorganic byproducts and CO2. 1.03 2. H₂O ofPlease don't provide handwritten solution.Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant, intermediates, and product in this condensation reaction. Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts. Drawing :0: :0: -CH3 OH CHзONA, CH3OH heat Q CH3ONa , CH3OH heat CH3 CH3ONA, CH3OH Select to Draw heat く D
- Draw structural formulas for all of the enol forms of the carbonyl compound belowNaNH2 is typically used instead of KOH to produce alkynes through elimination because NaNH2 is a stronger base. Explain why KOH can be used to create diphenylacetylene for this reaction. (think about proton acidity)Give detailed Solution with explanation needed. don't use Ai for answering this
- Give the IUPAC name for the following alkenes. Include an E/Z designation where appropriate. Part 1 of 2 Part 2 of 21 Give detailed Solution with explanation needed..don't give Handwritten answer. give also IUPAC Rules1. Explain how you could synthesize butane. Be sure to list all reactants and reagents required. 2. Explain how Hammond's postulate accounts for the higher selectivity of bromination reactions as compared to chlorination reactions.Checking my answer, there was difference with solution. (organic chemistry smith 5th ed 2.47P (d)) Solution said 'the acid base reaction between pentyne and ammonia is product way because pka of pentyne is 25, ammonia is 38 so pentyne will be deprotanted by ammonia.' but I think (and as written in the book) NH4+ is stronger acid than pentyne and acid-base reaction works when reactant is stronger acid than product conjugate acid. It isn't match that pentyne makes NH4+. who is incorrect?