Determine the required solids retention time (SRT) of a completely mixed activated sludge aeration tank for a conventional activated sludge system treating a design flow rate of 34,560 m³/d, where the effluent standards are 30.0 mg/L for BODs and 30.0 mg/L for total suspended solids (TSS). Assume that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the BODs concentration leaving the primary clarifier is 128 mg/L that the MLVSS concentration (X₂) is 2,500 mg/L. Assume the following values for the growth constants: Ks 100 mg/L BODS ⚫ Hm - 2.5 d 1 kd = 0.050 d 1 Y = 0.50 mg VSS/mg BODs removed Express your answer in days and round to the nearest 0.1.
Determine the required solids retention time (SRT) of a completely mixed activated sludge aeration tank for a conventional activated sludge system treating a design flow rate of 34,560 m³/d, where the effluent standards are 30.0 mg/L for BODs and 30.0 mg/L for total suspended solids (TSS). Assume that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the BODs concentration leaving the primary clarifier is 128 mg/L that the MLVSS concentration (X₂) is 2,500 mg/L. Assume the following values for the growth constants: Ks 100 mg/L BODS ⚫ Hm - 2.5 d 1 kd = 0.050 d 1 Y = 0.50 mg VSS/mg BODs removed Express your answer in days and round to the nearest 0.1.
Solid Waste Engineering
3rd Edition
ISBN:9781305635203
Author:Worrell, William A.
Publisher:Worrell, William A.
Chapter6: Biological Processes
Section: Chapter Questions
Problem 6.1P
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Transcribed Image Text:Determine the required solids retention time (SRT) of a completely mixed
activated sludge aeration tank for a conventional activated sludge system
treating a design flow rate of 34,560 m³/d, where the effluent standards are
30.0 mg/L for BODs and 30.0 mg/L for total suspended solids (TSS). Assume
that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the
BODs concentration leaving the primary clarifier is 128 mg/L that the MLVSS
concentration (X₂) is 2,500 mg/L. Assume the following values for the growth
constants:
Ks 100 mg/L BODS
⚫ Hm - 2.5 d 1
kd = 0.050 d 1
Y = 0.50 mg VSS/mg BODs removed
Express your answer in days and round to the nearest 0.1.
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