Determine the design flexural strength in ft kips of a W12 x 35 of A242 (Fy = 50ksi) steel subject toa. Continuous lateral support. Blank 1b. An unbraced length of 10 ft with Cb = 1.0. Blank 2C. An unbraced length of 20 ft with Cb = 1.0. Blank 3%3DW12x35A =10.30in 42d =12.500in.tw =0.300in.bf =6.560in.tf =0.520in.T=k =k1 =10-1/8in.0.8200in.0.7500in.3-1/2gage =rt =in.1.740in.d/Af =3.66Ix =285.00in.4in.43Sx =45.605.250in.ly =Sy =24.50in.47.47in.43ry =Zx =1.540in.51.20in 43Round off you answer to two decimal places.Zy =|11.50in.^3J=0.74in.^4Cw =879in.^6a =55.42in.Wno =19.60in.^2Sw =16.80in. 14Qf =Qw =9.75in.4325.40lin 43Blank 1Add your answerBlank 2Add your answerBlank 3 Add your answer

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Determine the design flexural strength in ft kips of a W12 x 35 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb =- 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3 W12x35 ... A = 10.30 in 2 12.500 in. tw = 0.300 in. bf = 6.560 in. tf = 0.520 in. T= 10-1/8 in. 0.8200 in. k1 = 0.7500 in. gage = rt = 3-1/2 in. 1.740 in. d/Af = 3.66 bx = 285.00 in.4 Sx = 45.60 in.43 IX = 5.250 in. ly = Sy = 24.50 in 4 7.47 in.43 ry = Zx = Zy = J= Cw = 1.540 in. 51.20 in.43 Round off you answer to two decimal places. 11.50 in.43 0.74 in.4 879 in. 6 a = Wno = 55.42 in. in.2 in 4 19.60 Sw = 16.80 Of= in.3 in 43 9.75 Qw = 25.40 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Determine the design flexural strength in ft kips of a W12 x 35 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb =- 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3 W12x35 ... A = 10.30 in 2 12.500 in. tw = 0.300 in. bf = 6.560 in. tf = 0.520 in. T= 10-1/8 in. 0.8200 in. k1 = 0.7500 in. gage = rt = 3-1/2 in. 1.740 in. d/Af = 3.66 bx = 285.00 in.4 Sx = 45.60 in.43 IX = 5.250 in. ly = Sy = 24.50 in 4 7.47 in.43 ry = Zx = Zy = J= Cw = 1.540 in. 51.20 in.43 Round off you answer to two decimal places. 11.50 in.43 0.74 in.4 879 in. 6 a = Wno = 55.42 in. in.2 in 4 19.60 Sw = 16.80 Of= in.3 in 43 9.75 Qw = 25.40 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.5.10P: If the beam in Problem 5.5-9 i5 braced at A, B, and C, compute for the unbr Cb aced length AC (same...

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