5-19. Compute the maximum total service live load that can be applied to the A36 sec- tion shown in the figure, if K,L, = 12 ft., K,L, = 10 ft. Assume the load is 1/2 dead load and 1/2 live load. Solve by both LRFD and ASD methods. (Ans. 29.0 k LRFD; 27.0 k ASD) 214 X 3 x - 4 in 3 in 3 in FIGURE PS-19

5-19. Compute the maximum total service live load that can be applied to the A36 sec- tion shown in the figure, if K,L, = 12 ft., K,L, = 10 ft. Assume the load is 1/2 dead load and 1/2 live load. Solve by both LRFD and ASD methods. (Ans. 29.0 k LRFD; 27.0 k ASD) 214 X 3 x - 4 in 3 in 3 in FIGURE PS-19

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The W36 x 135 beam shown carries service loads shown (excluding weight). It has been decided to add a 10-meter steel column at point B to eliminate excessive deflection. If the column being added is fixed at the bottom and pinned at the top, design the column that can withstand as support (Use a recommended value for K. Evaluate using LRFD and ASD). a. Use WT18 section b. Use W36 section c. Using the section at (b), determine the dimension of the base plate if the foundation dimension will be 1500mm x 1500mm. Pp = 88 kN PL = 163 kN Wp = 21 kN/m WL = 58 kN/m C B 6 m 12 m
a round steel rod made of structural steel, AISI c1020, as rolled, is to be used as a column, centrally loaded with 10kips and N=3. Determine the diamter for (a) L=25 in, (b) L=50in. The same as (a) and (b) except that the material is AISI 8640 OQT 1000 def F. Is there any advantage using this material rather than structural steel? * Complete Explanation and Solution
The beam-column shown is part of a frame not allowed to sway. The ultimate loadings on both x and y axis are shown. Use F, = 50 ksi and LRFD specs to check if W14x90 is adequate. 400k 400k 2K/ Sok-f 20 Sok-A 40ok A ook
iven a 4meter both ends fixed W8x21 steel column with Fy = 248MPa. Use ASEP steel manual for section properties. Identify what kind of failure or limit state does the column experience?
Q3) The beam shown in Figure below has lateral support at the ends only. The concentrated loads are live loads. Use A992 steel and select a W shape. (Do not check deflections. Use C-1). 23 k 25 k ttst
a. Select a W14 of A992 steel. Use the column load tables. 1. Use LRFD. 2. Use ASD. b. Select a W16 of A572 Grade 60 steel. Use the trial-and-error approach covered in Section 4.6 . Use LRFD. 2. Use ASD.
Question 1 of 5 Determine the maximum live load P, that the beam can carry. Use plastic analysis and LRFD provisions. A 36 steel Pu -PL 300X30 Wu 6m 4m PL300X15 Pd = 150kN Wd = 10kN/m, WL = 4kN/m, CS Scanned with CamScanner
Select a WT section for the compression member shown in Figure. The load is the total service load, with a live-to-dead load ratio of 2.5:1. Use Fy 5 50 ksi. a. Use LRFD. b. Use ASD 21' 175 k 1
Problem 6: Analyse to determine the maximum allowable tensile load for a W310x44.5 connected to a pair of 160x20mm gusset plates as shown in figure. Assume 4 holes at each critical section and use 436 steel and the AISC LRFD specification. The combined overload factor for dead and live load is to be 1.38. T2 T. T/2 20mm Diameter Rivets 2@60 Figure. Problem 6 (The shown dimensions are in mm)
The beam-column shown below is pinned at both ends and is subjected to the loads shown. Bending is about both the strong axis and weak axis. W14x82 A992 is used. Lateral support is provided at the ends only. Neglect the column weight. Use LRFD for solution. What is the governing φbMnx in ft-kips?
Select the lightest W section for the column shown in the accompanying figure. The loading is 30 kips dead load and 120 kips gravity live load. The member is built into a wall so that it may be considered as continuously braced in the weak direction. Note: Not all of the variable W sections are included in the AISC Manual "Available Strength in Axial Compression" tables. Use (a) A992 steel; (b) Fy = 60 ksi