determine the deflection of the free end of the beam.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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1. This question relates to the deflection of a statically indeterminant symmetric cross-section beam.
a) Briefly explain what you understand by the terms, (i)symmetrical beam and (ii)statically
indeterminant. Relate the stresses in a loaded beam to the equations below and describe how the
equation can be solved using Macauley brackets. Be sure to discuss all terms in the equation below
and provide a diagram to support your description.
EI d²y / dx² = M(x) and o/y=M/\=E/R
2. b) A square section beam is built into a support at its left-hand end and free at its right-hand
end. The deflects under its own weight, represented as a Uniformly Distributed Load, UDL. With
the beam's Young's modulus, E=150GPa, the UDL=120N/m and second moment of
area, |=10
3. c) Explain the principle of superposition and so determine the load on a prop that is now applied
at the free end of the beam.
-8.4
m and length, L=1.0m, determine the deflection of the free end of the beam.
Transcribed Image Text:1. This question relates to the deflection of a statically indeterminant symmetric cross-section beam. a) Briefly explain what you understand by the terms, (i)symmetrical beam and (ii)statically indeterminant. Relate the stresses in a loaded beam to the equations below and describe how the equation can be solved using Macauley brackets. Be sure to discuss all terms in the equation below and provide a diagram to support your description. EI d²y / dx² = M(x) and o/y=M/\=E/R 2. b) A square section beam is built into a support at its left-hand end and free at its right-hand end. The deflects under its own weight, represented as a Uniformly Distributed Load, UDL. With the beam's Young's modulus, E=150GPa, the UDL=120N/m and second moment of area, |=10 3. c) Explain the principle of superposition and so determine the load on a prop that is now applied at the free end of the beam. -8.4 m and length, L=1.0m, determine the deflection of the free end of the beam.
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