Density = (0.9M x 36.46g/mol)/36              = 32.814/36              = 0.9115g/mL My problem is that I don't understand where the 36 came from for "weight", and I need to be able to show all unit measurements for each step.  So my issue has 2 parts: 1) How was the Weight value determined to be 36 (I need to see the formula) 2) Where in the step-by-step process is mL in there so that after all cancellations/conversions are completed, the only remaining units are g/mL to show how 0.9115g/mL was arrived at.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I am trying to ascertain the density of 0.9-M HCl.  The book provides a density of 1.0-M HCl as 1.016g/mL.

I know the Molecular Weight aka Molar Mass is 36.46g/mol

I also know that the equation to calculate the density in this instand is:

Density=(Molarity x Molecular Weight)/Weight

I have found examples online, and one answer provided here that shows the Density of 0.9-M HCl is 0.9115g/mL.  That answer was arrived at as follows:

Density = (0.9M x 36.46g/mol)/36
             = 32.814/36
             = 0.9115g/mL

My problem is that I don't understand where the 36 came from for "weight", and I need to be able to show all unit measurements for each step. 

So my issue has 2 parts:

1) How was the Weight value determined to be 36 (I need to see the formula)

2) Where in the step-by-step process is mL in there so that after all cancellations/conversions are completed, the only remaining units are g/mL to show how 0.9115g/mL was arrived at.

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