Volume of HCL sample = 15ml Molarity standardized NaOh solution = .09929 Initial buret reading = 17.85 mL NaOH final buret reading = 36.16 mL NaOH volume of NaOH used = 17.31 Equation HCl = NaOH=NaCl + H2O How many moles of NaOH were used to reach the equivalence point?
Volume of HCL sample = 15ml Molarity standardized NaOh solution = .09929 Initial buret reading = 17.85 mL NaOH final buret reading = 36.16 mL NaOH volume of NaOH used = 17.31 Equation HCl = NaOH=NaCl + H2O How many moles of NaOH were used to reach the equivalence point?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Volume of HCL sample = 15ml
Molarity standardized NaOh solution = .09929
Initial buret reading = 17.85 mL NaOH
final buret reading = 36.16 mL NaOH
volume of NaOH used = 17.31
Equation HCl = NaOH=NaCl + H2O
How many moles of NaOH were used to reach the equivalence point?
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