25.00 mL of a solution of phosphoric acid, H3PO4, was titrated with 0.500 M NaOH. a) Write the balanced chemical equation for this reaction. b) If 35.92 mL of NaOH solution were needed to reach the end point in the titration, what is the molarity of the H3PO4 solution? c) How many grams of H3PO4 were present?

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Q: A chemistry student weighs out 0.0973 g of phosphoric acid (H3PO4, a triprotic acid, into a 250. mL…

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A: At equivalent point,  Geq. of NaOH  = Geq. of KHP N1V1 = N2V2 M × 16.8 /1000 = 0.261/204 M = 0.076M

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.