Determine the number of moles of citric acid per 240 mL of the vegtable juice.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Determine the number of moles of citric acid per 240 mL of the vegtable juice.

**Titration Data and Calculations**

A sample of 24.8 mL of vegetable juice is titrated with 15.65 mL of NaOH solution. The molar concentration of the NaOH solution is 0.106 M. The molar mass of citric acid is 192.12 g/mol.

**Instructions:**
Express all answers with 3 significant figures using appropriate units.

**Calculations:**

**2. Molar Concentration of Citric Acid:**

- Calculation: 
  \[
  \text{15.65 mL of NaOH} \times 0.106 \, \text{M} = 1.06589 \, \text{mmol}
  \]
  \[
  \frac{1.06589 \, \text{mmol citric acid}}{24.8 \, \text{mL of vegetable juice}} = 0.0429665441 \, \text{M} \rightarrow 0.0429 \, \text{M}
  \]

**3. Number of Moles of Citric Acid per 240 mL:**

To be calculated based on the molarity found in part 2.

**4. Mass of Citric Acid per 240 mL:**

To be calculated using the number of moles from part 3 and the molar mass of citric acid.

**5. Percent Error in Titration:**

If the label states 1 g of citric acid per 240 mL, calculate the percent error based on the mass found in part 4. Express the result with 2 significant figures.

For graph or diagram details, ensure to include clear labels and units for any plotted data to visualize results effectively.

**End of Calculations**
Transcribed Image Text:**Titration Data and Calculations** A sample of 24.8 mL of vegetable juice is titrated with 15.65 mL of NaOH solution. The molar concentration of the NaOH solution is 0.106 M. The molar mass of citric acid is 192.12 g/mol. **Instructions:** Express all answers with 3 significant figures using appropriate units. **Calculations:** **2. Molar Concentration of Citric Acid:** - Calculation: \[ \text{15.65 mL of NaOH} \times 0.106 \, \text{M} = 1.06589 \, \text{mmol} \] \[ \frac{1.06589 \, \text{mmol citric acid}}{24.8 \, \text{mL of vegetable juice}} = 0.0429665441 \, \text{M} \rightarrow 0.0429 \, \text{M} \] **3. Number of Moles of Citric Acid per 240 mL:** To be calculated based on the molarity found in part 2. **4. Mass of Citric Acid per 240 mL:** To be calculated using the number of moles from part 3 and the molar mass of citric acid. **5. Percent Error in Titration:** If the label states 1 g of citric acid per 240 mL, calculate the percent error based on the mass found in part 4. Express the result with 2 significant figures. For graph or diagram details, ensure to include clear labels and units for any plotted data to visualize results effectively. **End of Calculations**
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