200.0 mL of a 0.700 M solution of KCI is diluted to 600.0 mL. What is the new concentration of the solution? M 1 4 C 7 8 9 +/- х 100 + 3. 2.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem Statement:**

200.0 mL of a 0.700 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

**Calculator Interface Description:**

The interface features a numeric keypad with buttons labeled 1 through 9, 0, decimal point (.), and +/- for input. A backspace button and a clear button (C) are present for correcting entries. An additional "x 10" button allows for entering scientific notation. A red "+" button is located in the bottom right corner, potentially for submitting the answer.

This setup is designed to allow students to enter numerical answers directly into an online platform while calculating the new concentration after dilution using the dilution formula: 

\[ C_1V_1 = C_2V_2 \]

where:
- \( C_1 \) is the initial concentration (0.700 M)
- \( V_1 \) is the initial volume (200.0 mL)
- \( C_2 \) is the final concentration 
- \( V_2 \) is the final volume (600.0 mL)

The goal is to solve for \( C_2 \).
Transcribed Image Text:**Problem Statement:** 200.0 mL of a 0.700 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution? **Calculator Interface Description:** The interface features a numeric keypad with buttons labeled 1 through 9, 0, decimal point (.), and +/- for input. A backspace button and a clear button (C) are present for correcting entries. An additional "x 10" button allows for entering scientific notation. A red "+" button is located in the bottom right corner, potentially for submitting the answer. This setup is designed to allow students to enter numerical answers directly into an online platform while calculating the new concentration after dilution using the dilution formula: \[ C_1V_1 = C_2V_2 \] where: - \( C_1 \) is the initial concentration (0.700 M) - \( V_1 \) is the initial volume (200.0 mL) - \( C_2 \) is the final concentration - \( V_2 \) is the final volume (600.0 mL) The goal is to solve for \( C_2 \).
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