dc(t) = dt dT'(t) dt == V = 0.5 [m³] EkoCART (--koe #) C₁ (t) + (KCA) (t) + -AHko pCp + (음 eRT CA(t) + RT2 e Co (t) eRT T' (t) + #) + (DV) F KOCAAHE E PC₂RT² #) + (-/- R 8.314 [kJ-kmol¨¹.K¨¹] To 352.6634 [K] (1) Q'(t) (2) E = 8.314×104 [kJ-kmol¹] AH = -4.78×104 [kJ-kmol¹] ko 65x109 [min] Cp = 0.329 [kJ-kg 1-K] p = 1000 [kg.m³] F = 0.2 [m³-min¹] Cao = 0.6767 [kmol-m31 Q = 0 [kJ-min¹] CA =0.0199 [kmol·m³] T= 448.09 [K] G'D(s) 767.536 s²+13.61s+ 25.116 Q'(s) scope Pl(s) + ☑ Saturation for Q'(s) 1000 Gc(s) 1 12+1 G'M(s) T'(s) scope out.Q out.T -0.0131 s+13.61 G'A(s) CA(s) scope out.CA
dc(t) = dt dT'(t) dt == V = 0.5 [m³] EkoCART (--koe #) C₁ (t) + (KCA) (t) + -AHko pCp + (음 eRT CA(t) + RT2 e Co (t) eRT T' (t) + #) + (DV) F KOCAAHE E PC₂RT² #) + (-/- R 8.314 [kJ-kmol¨¹.K¨¹] To 352.6634 [K] (1) Q'(t) (2) E = 8.314×104 [kJ-kmol¹] AH = -4.78×104 [kJ-kmol¹] ko 65x109 [min] Cp = 0.329 [kJ-kg 1-K] p = 1000 [kg.m³] F = 0.2 [m³-min¹] Cao = 0.6767 [kmol-m31 Q = 0 [kJ-min¹] CA =0.0199 [kmol·m³] T= 448.09 [K] G'D(s) 767.536 s²+13.61s+ 25.116 Q'(s) scope Pl(s) + ☑ Saturation for Q'(s) 1000 Gc(s) 1 12+1 G'M(s) T'(s) scope out.Q out.T -0.0131 s+13.61 G'A(s) CA(s) scope out.CA
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
I need immediate help with my SIMULINK model. I don't know why but no matter how much a increase or decrease Kc or TI, the graphs are the same. C'A0(s) is the disturbance going through G'D(s). Please check my transfer function blocks by taking the laplace transform of the equations. Any suggestions is welcome greatly! thanks
![dc(t)
=
dt
dT'(t)
dt
==
V = 0.5 [m³]
EkoCART
(--koe #) C₁ (t) + (KCA) (t) +
-AHko
pCp
+ (음
eRT CA(t) +
RT2
e
Co
(t)
eRT T' (t) +
#) + (DV)
F KOCAAHE E
PC₂RT²
#) + (-/-
R 8.314 [kJ-kmol¨¹.K¨¹]
To 352.6634 [K]
(1)
Q'(t)
(2)
E = 8.314×104 [kJ-kmol¹]
AH = -4.78×104 [kJ-kmol¹]
ko 65x109 [min]
Cp = 0.329 [kJ-kg 1-K]
p = 1000 [kg.m³]
F = 0.2 [m³-min¹]
Cao = 0.6767 [kmol-m31
Q = 0 [kJ-min¹]
CA =0.0199 [kmol·m³]
T= 448.09 [K]
G'D(s)
767.536
s²+13.61s+ 25.116
Q'(s) scope
Pl(s)
+
☑
Saturation for Q'(s)
1000
Gc(s)
1
12+1
G'M(s)
T'(s) scope
out.Q
out.T
-0.0131
s+13.61
G'A(s)
CA(s) scope
out.CA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca6b5de9-d666-4be4-bec5-372f49facd74%2Ff13311d4-8465-4d3d-b8a4-5eb951d3ca5c%2Fun6kjv_processed.png&w=3840&q=75)
Transcribed Image Text:dc(t)
=
dt
dT'(t)
dt
==
V = 0.5 [m³]
EkoCART
(--koe #) C₁ (t) + (KCA) (t) +
-AHko
pCp
+ (음
eRT CA(t) +
RT2
e
Co
(t)
eRT T' (t) +
#) + (DV)
F KOCAAHE E
PC₂RT²
#) + (-/-
R 8.314 [kJ-kmol¨¹.K¨¹]
To 352.6634 [K]
(1)
Q'(t)
(2)
E = 8.314×104 [kJ-kmol¹]
AH = -4.78×104 [kJ-kmol¹]
ko 65x109 [min]
Cp = 0.329 [kJ-kg 1-K]
p = 1000 [kg.m³]
F = 0.2 [m³-min¹]
Cao = 0.6767 [kmol-m31
Q = 0 [kJ-min¹]
CA =0.0199 [kmol·m³]
T= 448.09 [K]
G'D(s)
767.536
s²+13.61s+ 25.116
Q'(s) scope
Pl(s)
+
☑
Saturation for Q'(s)
1000
Gc(s)
1
12+1
G'M(s)
T'(s) scope
out.Q
out.T
-0.0131
s+13.61
G'A(s)
CA(s) scope
out.CA
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