In the circuit shown, let R₁-7, R₂-12, R3-24, R4-2, V₁ =17, V2 -68, and V3-51, to calculate the powerdelivered (or absorbed) by the circuit inside the box, as follows:{NOTE: On Multiple Choice Questions, like this problem, you have only one attempt }1. The current I is equal to (choose the closed values in amperes)-0.7910-0.7563.0220.756(A)-3.0220.7912. The power delivered (or absorbed) (choose the closest value in watts) (W)373.3450-373.345-52.23452.23465.079O-24.833R₁V₂R3R₂wwwV3V₁wwwR4

Answered: In the circuit shown, let R₁-7, R₂-12,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Now let's try using a pack of AA batteries (1.2 V output voltage and 0.2 Ohm internal resistance each) to replace the lead-acid battery. In order to match the car lead-acid battery, first, 10 such AA batteries need to be connected in series to form a 12V cell, while 50 such cells need to be connected in parallel (as shown in picture above; the total of 500 AA batteries are used). Find the power that is supplied to the same "car starter" using this pack of AA batteries. (Hint: for the second question, you need to find the total voltage and the internal resistance of the whole pack; you also need to find the resistance of the "car starter"; this can be done using the data of the first part of this problem)
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Sample Problem continued with solution process Step 1: Drawing a circuit diagram and labeling the unknowns. All told there are 5 elements, 4 resistors and 1 voltage source. For resistors I intentionally label the currents going from + to -. That way, I can write V = I R. If I labeled the current through a resistor from – to + as I, then I have to write the equation by Ohm's law as V = -I R. For convenience I label the current i, through the voltage source from – to +. (There is no Ohm's law for a source to follow. Do not try to have a resistance in a source. What is a V, 3 + (1 |1A 10 Ω + V, iş V2 20 i2 V3 + 2 20Ω 4 İz I then examine the circuit. I see that this is a obvious consequence of the labeling: iz = i,= i, All are current going through one path with the same direction as I labeled. If I had labeled one in the opposite direction, I just had to put in a minus sign. source? A voltage source is to guarantee the voltage drop from its + to its – a fixed voltage V,. I denote four…
Vi Ri Vo Il The elements in the circuit shown have the following values: R = 2570.11 N. R2 = 4277.34 N. R3 = 4236.39 N. R4 = 622.17 N. Vị = 102.816373 V. h = 0.0176 A. Determine the following: a.) Using any circuit method you prefer, solve for the voltage V, b.) Determine the current flowing through R4. c.) Determine the magnitude of the current flowing through the resistor R3 (Hint: Assume the current flows up through R3). d.) Determine the power dissipated by R4 (in Watts).

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