Date TestedNameCourse Code / SectionGroup NumberSample NumbersSample DescriptionRELATIVE DENSITY DETERMINATIONDATA SHEETMass of empty mold:Diameter of empty mold:Height of empty mold:Mass of mold and soil (M₁):Average initial dial gauge reading (R₁):Average final dial gauge reading (R):Thickness of surcharge base plate (Tp):Mass of mold and soil (M₂):COMPUTATION AND DISCUSSION OF RESULTS: DATA FOR RELATIVE DENSITY TESTMass of empty mold:Diameter of empty mold:Height of empty mold:Mass of mold and soil (M1):Height of loss in:Mass of mold and soil (M2):Specific Gravity of soil solids5.258 kg10.15 cm16.40 cm6.691 kg3.775 cm6.394 kg2.65

Given data, Mass of empty mold(M) 5.258 kg Diameter of empty mold 10.15 cm Height of empty…

DATA FOR RELATIVE DENSITY TEST Mass of empty mold: Diameter of empty mold: Height of empty mold: Mass of mold and soil (M1): Height of loss in: Mass of mold and soil (M2): Specific Gravity of soil solids 5.258 kg 10.15 cm 16.40 cm 6.691 kg 3.775 cm 6.394 kg 2.65

DATA FOR RELATIVE DENSITY TEST Mass of empty mold: Diameter of empty mold: Height of empty mold: Mass of mold and soil (M1): Height of loss in: Mass of mold and soil (M2): Specific Gravity of soil solids 5.258 kg 10.15 cm 16.40 cm 6.691 kg 3.775 cm 6.394 kg 2.65

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Shrinkage Limit Test Weight of Dish with petroleum jelly (g) 11.3015 Weight of Dish with petroleum…

Q: Situation 3: Consider the following shrinkage limit test using mercury. Mass of moisture can: 16.5 g…

Q: From the table shows a summary of a liquid limit and plastic limit test. Compute the plasticity…

A: Plasticity index The plasticity index is reported as a percentage of the soil sample's dry weight.…

Q: Q1: The results of a standard Proctor test are given in the table. The volume of the proctor mold…

A: Standard proctor test is a laboratory method used to determine the moisture content at which soil…

Q: The following data is for 1 g sample of granular powder Volume of solid = 0.3 cm¹ / g Volume of…

A: Given:- The mass of the granular powder = 1 g The volume of solid = 0.3 cm3/g The volume of the…

Q: 2. The results of the standard proctor test are given in the following table. Test Number Volume of…

A: Given:- Test number Volume of proctor mold (cm3) Moist weight of wet soil in the mold (kg)…

Q: , g 19.44 18.78 18.75 22.10 Weight of container, g 12.74 13.24 13.20 13.27 Weight of…

Q: A core sample has a cross sectional area of 1 cm2 and a length of 5 cm. Water with a viscosity of 1…

A: Given dataCross sectional Area=A=1 cm2Length(L)=5 cmViscosity=V=1 cp=1×10-7Ns/cm2Q1=20.4300=0.0680…

Q: he results of sieve analysis are shown below. Sieve No. Opening Size (mm) Mass Retained (g) 4 4.75…

A: Sieve Analysis: It is an analysis done in order to obtain the particle size distribution allowing…

Q: 1/30 1/30 3.88 3.87 1/30 3.87 1/30 3.77 . a. Determine the moist unit weight (ymoist) and dry unit…

Q: 1. An air dry (not oven dry) processed clay powder sample has the following measurements: - Mass of…

Q: The following are the result of shrinkage limit test. Vo (Saturated State) 25.4 cm3 Vf (Dry State)…

A: Given data - Vo ( saturated state ) = 25.4 cm3 Vf (Dry State) = 16.1 cm3 mo (Saturated State) =…

Q: Example: Marshall test results of surface course for six specimens gave the following results: Unit…

A: As per Marshall specifications, the optimum bitumen content can be found out by taking the average…

Q: Plot the dry density versus the water content and determine the maximum dry density and optimum…

A: To Plot the dry density versus the water content curve and to determine the maximum dry density and…

Q: Situation 3: Consider the following shrinkage limit test using mercury. Mass of moisture can: 16.5 g…

Q: A column analysis of a flocculating suspension is shown below. The initial solids concentration is…

A: C0 = Intital solids concentration = 200 mg/L(a) Calculate the removal fraction at each depth and…

Q: 1. A sample of dry coarse-grained material was shaken through a nest of sieves and the following…

A: It is given sample of dry coarse-grained material and asked to determine effective size,…

Q: • Problem 2- . The following are the results of a sieve analysis. Determine the percent finer than…

Q: a. what is the effective size diameter? b. what is the uniformity coefficient?

Q: The volume of an irregular partially saturated soil sample has been determined by covering the…

Q: Sand cone method was used to determine the density of the soll in a certain area. The following data…

A: Given: Weight of proctor moldWpm=5173 g. Weight of proctor mold with sandWpms=7147 g. Volume of…

Q: Soil Compaction 1. A series of Modified Proctor Tests have been perfomed on a soil that has a unit…

Q: Test No. Item 1. Can no. 1.5g 22,12 g 20.42 g Mass of can, M, (g) Mass of can + moist soil, M2 (g)…

A: Solution Given Data Mass of Can M1= 1.5 g Mass of can+moist soil, M2= 22.12 g Mass of can+Dry Soil,…

Q: on, the mass of the soil sample inside a mold is estimated as 1710 grams. After drying, its mass was…

A: Given:- mass of the soil sample inside a mold is estimated=1710 grams To find:- a) On the phase…

Q: Problem A mold having a volume of 0.12ft was filled with moist soil. The weight of the soil in the…

Q: Determine the following: a.) %F2,F3,F4,F5,F6,F7,F8 Assuming that D60 = 0.297; D30 = 0.172; D10 =…

Q: Soil placed on a can has been weighed before and after an oven-drying procedure. The procedure…

Q: What is dry unit weight of the soil sample below (va) in Ib/ft ? The combined weight of a mold and…

A: Given data : Combined weight of mold and compacted soil sample (W1)=8.7 lbMold weight (W2)=5 lbmolds…

Q: U.S Sieve No Opening (mm) Mass of soil retained (g) 4 4.75 28 10…

A: KINDLY NOTE, as per our company guidelines we are supposed to answer only first sub-parts. Kindly…

Q: Soil placed on a can has been weighed before and after an oven-drying procedure. The procedure…

Q: A sample in variable head permeameter with 80 mm in diameter and 180 mm height can estimate the…

A: solution diameter of sample d=80mmso Area A=π4×802=5026.55 mm2length of the sampel…

Q: 2.9 A hydrometer test has the following results: G, = 2.7, temperature of water = 24°C, and L = 9.2…

Q: A Standard Proctor Test was completed according to Method A described in Chapter 12. The following…

Q: The laboratory test data for a standard Proctor test are given below. Volume of Moisture content…

Q: 943.3 1.70 943.3 1.85 943.3 1.90 943.3 1.99 943.3 2.05 943.3 1.96 943.3 1.92

A: Standard proctor test Moist unit weight = wet soil / volume Dry unit weight = moist unit weight /…

Q: A plastic limit test has been performed on a soil. Threads of the soil that broke at a diameter of…

A: The mass of the wet soil is calculated by subtracting the mass of the can from the mass of the soil…

Q: 1. An air dry (not oven dry) processed clay powder sample has the following measurements: - Mass of…

Q: A sample of clay soil of volume 1/1000 cubic meter and mass of 1.762 kg, after being dried out in an…

Q: A 2850 g and 2380 g mass for wet and dry soil were obtained respectively during the conduct of…

Q: A Standard Proctor Test was completed according to Method A described in Chapter 12. The following…

A: Standard Proctor test: By eliminating air spaces, compaction densifies soil by making it more…

Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

Date Tested
Name
Course Code / Section
Group Number
Sample Numbers
Sample Description
RELATIVE DENSITY DETERMINATION
DATA SHEET
Mass of empty mold:
Diameter of empty mold:
Height of empty mold:
Mass of mold and soil (M₁):
Average initial dial gauge reading (R₁):
Average final dial gauge reading (R):
Thickness of surcharge base plate (Tp):
Mass of mold and soil (M₂):
COMPUTATION AND DISCUSSION OF RESULTS:

DATA FOR RELATIVE DENSITY TEST
Mass of empty mold:
Diameter of empty mold:
Height of empty mold:
Mass of mold and soil (M1):
Height of loss in:
Mass of mold and soil (M2):
Specific Gravity of soil solids
5.258 kg
10.15 cm
16.40 cm
6.691 kg
3.775 cm
6.394 kg
2.65

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The following are the results of the laboratory shrinkage limit test (using mercury for displacement method). Note: Let us use the data for computation purposes only. Use the density of mercury instead of using the density of water. Weight of coated shrinkage limit dish, (g) 12.34 Weight of dish + wet soil, (g) 40.43 Weight of dish + dry soil, (g) 33.68 Weight of mercury to fill the dish, (g) 198.83 Weight of mercury displaced by soil pat, (g) 150.30
Mass of soil chunk = 537.5 g Mass of soil chunk + paraffin coating = 544.4 g Amount of water displaced after soil + paraffin was submerged in water = 250.0 cu cm Moisture Determination Wet mass of soil obtained during preparation of soil chunk = 173.9g Dry Mass of soil after oven drying = 155.0 g Specific gravity of soil (from experiment Sp. Gr. Determination) Specific gravity of paraffin used = 0.9
LIQUID AND PLASTIC LIMIT Please help me analyze data obtained from our atterberg experiment. What do these findings say about Liquid and Plastic limit. How can I relate these to real-world engineering practice?
Situation 5: Following is the result of a standard proctor test. Proctor mold Volume (cm³) 943.3 943.3 943.3 943.3 943.3 Unit Weight Trial 1 2 5 6 7 8 943.3 943.3 943.3 Mass of wet soil in Moisture content the mold (KG) 1.68 1.71 1.77 1.83 1.86 1.88 1.87 1.85 (56) 9.9 10.6 12.1 13.8 15.1 17.4 9 19.4 21.2 5d. Plot the compaction curve using the following plane, make sure to label the y-axis with the dry unit weights. Compaction Curve Water Content 5b. What is maximum dry unit weight and its corresponding water content? 5c. Considering a requirement of 97% compaction, what is the minimum dry unit weight that must be achiewed and what are the water contents that correspond to this dry unit weight?
Geotechnical engineering soil mechanics What are the percentages by mass of gravel, sand , sily and clay particles in the soil sample following the USCS standard size.
Cumpute the plasticity index and liquidity index
Atterberg's limits Problem 4.3 Results from liquid and plastic limit tests conducted on a soil are given below. Liquid limit tests: Number of Moisture blows, N content (%) 13 33 18 27 29 22 Plastic limit tests: Weight of Can 20 g Weight of Can + Moist soil = Weigh of Can + Dry soil 56.2 g 48.4 g a. Draw the flow curve and obtain the liquid limit. b. Calculate Plastic Limit b. What is the plasticity index of the soil?
Sample 2: Mass with empty mold M1 Mass of soil and mold M2 Hydraulic Head h Time interval t Volume V 145 g 250 g 950 mm 0.34 min 0.0046 L 145 g 260 g 900 mm 0.33 min 0.0049 L 145 g 228 g 922 mm 0.30 min 0.0051 L 145 g 281 g 915 mm 0.29 min 0.0044 L 145 g 219 g 908 mm 0.39 min 0.0042 L The diameter of the mold = 2.5 cm, Length of the sample = 0.3 m can u pls Find the permeability coefficient Mass of the soil Bulk Density Dry Density thank you Void Ratio
What is the moisture contect for 2
From the observed data in a pycnometer test indicated in the table above, determine the specific gravityof the soil solids.
Find the Cu of the given sample. identify the answer in this choices. Weight Percentage Cumulative Percentage Sieve retained finer S.NO Weight retained (gm) percentage retained (C)N = (100 - C) Select one: size (gm) {W,/ W,}x 100 O a. 8.98 1 75mm 100 O b. 18.33 63mm 100 О с. 2.92 3 50mm 100 O d. 6.22 4 37.5mm 454 22.7 22.7 77.30 28mm 285 14.25 36.95 63.05 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 9 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 -99.6 = 0.4 % of material 2. 5.
Correct answer please.