The laboratory test data for a standard Proctor test are given below. Volume of Moisture content Mass of wet soil in the mold (kg) Proctor mold (%) (ст3) 943.3 1.65 10 943.3 1.75 12 943.3 1.83 14 943.3 1.81 16 943.3 1.76 18 943.3 1.70 20 a) Find the maximum dry unit weight and optimum moisture content. b) Calculate the zero-air-void unit weights for a soil with G =2.68 at moisture content of

Q: Following the sieve analysis and the specific gravity of "SAND 1", a hydrometer test was performed…

A: The hydrometer test is used to determine the distribution of soil particle sizes that are smaller…

Q: Determine the liquid limit. LL = b. Determine the flow index. Flow index = Determine the liquidity…

A: Given Data: The plastic limit for the first trial is, PL1=16.2% The plastic limit for the second…

Q: 2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in…

A: Find the corresponding dry densities of the given water content results from Standard Proctor Test…

Q: A laboratory proctor test was conducted and the following data were obtained for the 5 trial…

A: Proctor test results are given, we need to plot compaction curve and determine dry unit weight and…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

A:

Q: A laboratory test was conducted according to Method A of the ASTM D4318 to find the liquid limit of…

A: The wet mass of the soil sample with the mass of the can is measured, again the dry mass of the…

Q: 1. A soil sample is collected at 20 °C and taken to the laboratory. The sample is in a stainless…

A: A soil sample in stainless steel cylinder is given with the weight of the cylinder and weight of…

Q: Question 4 Listen The principal objection to the use of the microwave oven for water-content…

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Q: Question 9 Soil placed on a can has been weighed before and after an oven-drying procedure. The…

A:

Q: A standard Proctor Test has yielded the values shown below. Determine: (a) The maximum dry unit…

A:

Q: A sample of sand has the following properties: Moist sand Dry sand Absorption 605 grams 550 grams…

A: solution Given Moist sand Msat=605 gramsDry sand Mdry=550gramsAbsorption =2%so the amount of water…

Q: A sample of soil was tested in the laboratory, and the test results were listed as shown in the…

A: As percent passing No. 200 (58.8%)is more than 36%, the soil is either A4,A5,A6 or A7 depending on…

Q: 2. Table 2 shows the results of the standard proctor test Water content (%) Weight (kg) 14 16,5 18,5…

A: Volume of mold = 943 cm3  Specific gravity of solids, Gs = 2.7

Q: A large soil sample obtained from a borrow pit has a wet mass of 26.50kg. The in-place volume…

A: Wet mass at borrow pit (WT) = 26.50 kg Volume of mass (VT) = 0.013 m3 Sample of wet soil (wT) = 135…

Q: The container 393 M A-Determine the optimum moisture content and the maximum dry unit weight B-what…

A: Givenwt of container = 20 Nwt of compacted soil (N) = wt of container and compacted soil (N) - wt of…

Q: Plot the moisture density curve and determine the maximum dry unit weight of compaction and the…

A: See density curve belowMaximum dry unit weight of compaction = 120.3 lb/ft^3Optimum moisture content…

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.