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A Standard Proctor Test was completed according to Method A described in Chapter 12. The following laboratory data was obtained: Mass of mold = Mass of moist specimen and mold = Volume of compaction mold = Mass of container= 51.5g Mass of container plus moist soil= 261.85g Mass of container plus oven-dried soil= 231.83g 1.98 kg 3.718 kg 0.0009438m3 4 Determine the Dry density of compacted specimen. (expressed in Mg/m³, 3 decimal places) Your Answer:

A Standard Proctor Test was completed according to Method A described in Chapter 12. The following laboratory data was obtained: Mass of mold = Mass of moist specimen and mold = Volume of compaction mold = Mass of container= 51.5g Mass of container plus moist soil= 261.85g Mass of container plus oven-dried soil= 231.83g 1.98 kg 3.718 kg 0.0009438m3 4 Determine the Dry density of compacted specimen. (expressed in Mg/m³, 3 decimal places) Your Answer:

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A Standard Proctor Test was completed according to Method A described in Chapter 12. The following laboratory data was obtained: Mass of mold = Mass of moist specimen and mold = Volume of compaction mold = Mass of container= 51.5g Mass of container plus moist soil= 261.85g Mass of container plus oven-dried soil= 231.83g 1.98 kg 3.718 kg 0.0009438m3 Determine the Dry density of compacted specimen. (expressed in Mg/m3, 3 decimal places) Your Answer:
Transcribed Image Text:A Standard Proctor Test was completed according to Method A described in Chapter 12. The following laboratory data was obtained: Mass of mold = Mass of moist specimen and mold = Volume of compaction mold = Mass of container= 51.5g Mass of container plus moist soil= 261.85g Mass of container plus oven-dried soil= 231.83g 1.98 kg 3.718 kg 0.0009438m3 Determine the Dry density of compacted specimen. (expressed in Mg/m3, 3 decimal places) Your Answer:
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