d. For the reaction2CH3OH(1) +302(g) → 2CO2(g) + 4H₂O(1)Sº J/(mol-K)SpeciesCH3OH (1)O₂(g)CO₂(g)H₂O(l)AS⁰ =126.8205.0213.769.95J/K Calculate AS for the following reactions, using standard entropy values from the table below.a. For the reactionSpecies Sº J/(mol-K)Al(s)O2(g)Al₂O3 (8)AS⁰ =4Al(s) + 30₂ (g) → 2Al2O3(s)28.28205.0b. For the reactionASO50.95=SpeciesHCN (1)O₂(g)H₂O(g) 188.7CO₂(g) 213.7N₂(g)AS⁰ =4HCN (1) +50₂ (g) → 2H₂O(g) + 4CO2 (g) + 2N2 (9)SJ/(mol.K)J/K112.8c. For the reaction205.0191.6Species S J/(mol.K)SO₂(g) 248.1H₂S(g) 205.6S(s)H₂O(g)SO2(g) + 2H₂S(g) → 3S(s) + 2H₂O(g)32.06J/K188.7J/K

(d) Given: SCH3OHo=126.8 J/mol·KSO2o=205.0 J/mol·KSCO2o=213.7 J/mol·KSH2Oo=69.95 J/mol·K

Answered: d. For the reaction 2CH3OH(1) + 302(g)…

d. For the reaction 2CH3OH(1) + 302(g) → 2CO2 (g) + 4H₂O(1) Sº J/(mol-K) Species CH, OH (1) 0₂ (9) CO₂(g) H₂O(l) ASO = 126.8 205.0 213.7 69.95 J/K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

d. For the reaction
2CH3OH(1) +302(g) → 2CO2(g) + 4H₂O(1)
Sº J/(mol-K)
Species
CH3OH (1)
O₂(g)
CO₂(g)
H₂O(l)
AS⁰ =
126.8
205.0
213.7
69.95
J/K

Calculate AS for the following reactions, using standard entropy values from the table below.
a. For the reaction
Species Sº J/(mol-K)
Al(s)
O2(g)
Al₂O3 (8)
AS⁰ =
4Al(s) + 30₂ (g) → 2Al2O3(s)
28.28
205.0
b. For the reaction
ASO
50.95
=
Species
HCN (1)
O₂(g)
H₂O(g) 188.7
CO₂(g) 213.7
N₂(g)
AS⁰ =
4HCN (1) +50₂ (g) → 2H₂O(g) + 4CO2 (g) + 2N2 (9)
SJ/(mol.K)
J/K
112.8
c. For the reaction
205.0
191.6
Species S J/(mol.K)
SO₂(g) 248.1
H₂S(g) 205.6
S(s)
H₂O(g)
SO2(g) + 2H₂S(g) → 3S(s) + 2H₂O(g)
32.06
J/K
188.7
J/K

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