The synthesis of solid lead (II) sulfide can be expressed in the equation Pb(s) + S(s) → PbS(s) AH° = - 98.7 kJ/mole Pb(s) → Pb(g) AH° (1) Pb(g) → Pb*(g) + 2 e1 Дн (2) S(s) → S(g) AH° (3) S(g) + 2 e → S(g) AH° (4) Pb (g) + s (g) → PbS(s) Дн (5) 17. Which statement about this reaction as temperature is increased is most reasonable? (A) This reaction will always be thermodynamically favored because the entropy change is expected to be positive. (B) This reaction will become thermodynamically favored because the entropy change is expected to be positive. (C) This reaction will become thermodynamically unfavored because the entropy change is expected to be negative. (D) This reaction will always be thermodynamically unfavored because the entropy change is expected to be positive.

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The synthesis of solid lead (II) sulfide can be expressed in the equation
Pb(s) + S(s) → PbS(s)
AH° = - 98.7 kJ/mole
Pb(s) → Pb(g)
AH° (1)
Pb(g) → Pb*2(g) + 2 e1
AH° (2)
S(s) → S(g)
AH° (3)
S(g) + 2 e1 → s'(g)
AH° (4)
Pb*(g) + S?(g) → PbS(s)
AH° (5)
17. Which statement about this reaction as temperature is increased is most reasonable?
(A) This reaction will always be thermodynamically favored because the entropy change
is expected to be positive.
(B) This reaction will become thermodynamically favored because the entropy change
is expected to be positive.
(C) This reaction will become thermodynamically unfavored because the entropy change
is expected to be negative.
(D) This reaction will always be thermodynamically unfavored because the entropy change
is expected to be positive.
18. If 5.0 grams of lead and 1.0 grams of sulfur are reacted according to the equation above, what will
be left in measurable amounts in the reaction vessel?
(A) Lead and lead sulfide only.
(B) Lead sulfide and sulfur only.
(C) Lead sulfide only.
(D) Lead sulfide, lead, and sulfur.
19. Which of the following will have the same numerical value as the lattice energy?
(A)
ΔΗ (1 ) + ΔΗ"(2)
(B)
AH°(3)
(C)
AH°(4)
(D)
AH°(5)
Transcribed Image Text:The synthesis of solid lead (II) sulfide can be expressed in the equation Pb(s) + S(s) → PbS(s) AH° = - 98.7 kJ/mole Pb(s) → Pb(g) AH° (1) Pb(g) → Pb*2(g) + 2 e1 AH° (2) S(s) → S(g) AH° (3) S(g) + 2 e1 → s'(g) AH° (4) Pb*(g) + S?(g) → PbS(s) AH° (5) 17. Which statement about this reaction as temperature is increased is most reasonable? (A) This reaction will always be thermodynamically favored because the entropy change is expected to be positive. (B) This reaction will become thermodynamically favored because the entropy change is expected to be positive. (C) This reaction will become thermodynamically unfavored because the entropy change is expected to be negative. (D) This reaction will always be thermodynamically unfavored because the entropy change is expected to be positive. 18. If 5.0 grams of lead and 1.0 grams of sulfur are reacted according to the equation above, what will be left in measurable amounts in the reaction vessel? (A) Lead and lead sulfide only. (B) Lead sulfide and sulfur only. (C) Lead sulfide only. (D) Lead sulfide, lead, and sulfur. 19. Which of the following will have the same numerical value as the lattice energy? (A) ΔΗ (1 ) + ΔΗ"(2) (B) AH°(3) (C) AH°(4) (D) AH°(5)
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