C(s) + ½ O2  (g) ↔ CO(g)                  ΔH°298 = -26,40 Kcal/gmol C(s) +  O2  (g) ↔ CO2(g)                 ΔH°298 = -94,05 Kcal/gmol 2Fe(s) + 3/2 O2 (g) ↔ Fe2O3 (s)        ΔH°298 = -196,30 Kcal/gmol The above reactions at 25oC and 1 atm. Calculate the reaction enthalpy (heat) of the following reaction in the standard case by using the reaction temperatures in the standard state: Fe2O3 (s) + 3 CO(g) ↔ 2Fe(s) + 3 CO2 (g)            ΔH°298 = ?

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