Write the Nernst equation and calculate the EMF of the following cell at 298 K. Mg(s) / Mg2+ (0.001 M) // Cu²+ (0.0001 M) / Cu(s) Eº = -2.37 V Eº Cu² /Cu = 0.34 V; Mg/Mg

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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**Problem:**

Write the Nernst equation and calculate the EMF of the following cell at 298 K.

Cell representation: Mg(s) / Mg²⁺ (0.001 M) // Cu²⁺ (0.0001 M) / Cu(s)

Given:
- \( E^\circ_{\text{Cu}^{2+}/\text{Cu}} = 0.34 \, \text{V} \)
- \( E^\circ_{\text{Mg}^{2+}/\text{Mg}} = -2.37 \, \text{V} \)

**Solution:**

To calculate the EMF, we need to apply the Nernst equation.

**Nernst Equation:**

\[ E = E^\circ - \frac{RT}{nF} \ln Q \]

Where:
- \( E \) is the cell potential under non-standard conditions
- \( E^\circ \) is the standard cell potential
- \( R \) is the universal gas constant \((8.314 \, \text{J mol}^{-1} \text{K}^{-1})\)
- \( T \) is the temperature in Kelvin \((298 \, \text{K})\)
- \( n \) is the number of moles of electrons transferred in the reaction
- \( F \) is Faraday's constant \((96485 \, \text{C mol}^{-1})\)
- \( Q \) is the reaction quotient

**Standard Cell Potential Calculation:**

\[ E^\circ_{\text{cell}} = E^\circ_{\text{Cu}^{2+}/\text{Cu}} - E^\circ_{\text{Mg}^{2+}/\text{Mg}} \]
\[ E^\circ_{\text{cell}} = 0.34 \, \text{V} - (-2.37 \, \text{V}) \]
\[ E^\circ_{\text{cell}} = 2.71 \, \text{V} \]

**Reaction Quotient \( Q \):**

\[ Q = \frac{[\text{Mg}^{2+}]}{[\text{Cu}^{2+}]} \]
\[ Q = \frac{0.001}{0.0001} \]
\[ Q = 10 \]

**Applying the Nernst Equation:**
For this reaction, the number of electrons \(
Transcribed Image Text:**Problem:** Write the Nernst equation and calculate the EMF of the following cell at 298 K. Cell representation: Mg(s) / Mg²⁺ (0.001 M) // Cu²⁺ (0.0001 M) / Cu(s) Given: - \( E^\circ_{\text{Cu}^{2+}/\text{Cu}} = 0.34 \, \text{V} \) - \( E^\circ_{\text{Mg}^{2+}/\text{Mg}} = -2.37 \, \text{V} \) **Solution:** To calculate the EMF, we need to apply the Nernst equation. **Nernst Equation:** \[ E = E^\circ - \frac{RT}{nF} \ln Q \] Where: - \( E \) is the cell potential under non-standard conditions - \( E^\circ \) is the standard cell potential - \( R \) is the universal gas constant \((8.314 \, \text{J mol}^{-1} \text{K}^{-1})\) - \( T \) is the temperature in Kelvin \((298 \, \text{K})\) - \( n \) is the number of moles of electrons transferred in the reaction - \( F \) is Faraday's constant \((96485 \, \text{C mol}^{-1})\) - \( Q \) is the reaction quotient **Standard Cell Potential Calculation:** \[ E^\circ_{\text{cell}} = E^\circ_{\text{Cu}^{2+}/\text{Cu}} - E^\circ_{\text{Mg}^{2+}/\text{Mg}} \] \[ E^\circ_{\text{cell}} = 0.34 \, \text{V} - (-2.37 \, \text{V}) \] \[ E^\circ_{\text{cell}} = 2.71 \, \text{V} \] **Reaction Quotient \( Q \):** \[ Q = \frac{[\text{Mg}^{2+}]}{[\text{Cu}^{2+}]} \] \[ Q = \frac{0.001}{0.0001} \] \[ Q = 10 \] **Applying the Nernst Equation:** For this reaction, the number of electrons \(
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