The volume of a liquid varies with temperature according to the following relationship: (³) -(0.75 V = V300K * 0.75 +3.9 * 10-4 (1) + 1.48 * 10-6 where V300k is the liquid's volume at 300K. Calculate the expansion coefficient of this liquid, x, at 320K.
The volume of a liquid varies with temperature according to the following relationship: (³) -(0.75 V = V300K * 0.75 +3.9 * 10-4 (1) + 1.48 * 10-6 where V300k is the liquid's volume at 300K. Calculate the expansion coefficient of this liquid, x, at 320K.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![The volume of a liquid varies with temperature according to the following relationship:
\[ V = V_{300K} \times \left( 0.75 + 3.9 \times 10^{-4} \left( \frac{T}{K} \right) + 1.48 \times 10^{-6} \left( \frac{T}{K} \right)^2 \right) \]
where \( V_{300K} \) is the liquid’s volume at 300K. Calculate the expansion coefficient of this liquid, \(\alpha\), at 320K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F424482ac-ef50-4214-a1e3-aaaeb325792a%2F7ef074ef-1841-47d6-a8a0-b44d27c1ffae%2F82zqjk6_processed.png&w=3840&q=75)
Transcribed Image Text:The volume of a liquid varies with temperature according to the following relationship:
\[ V = V_{300K} \times \left( 0.75 + 3.9 \times 10^{-4} \left( \frac{T}{K} \right) + 1.48 \times 10^{-6} \left( \frac{T}{K} \right)^2 \right) \]
where \( V_{300K} \) is the liquid’s volume at 300K. Calculate the expansion coefficient of this liquid, \(\alpha\), at 320K.
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