Create a MATLAB Script to do a cubic spline using the MATLAB spline function and plot the points and the curve. Test it for the following data sets. a. x = [1 2 3] and y = [148] b. x[-1012] and y = [ 1/3 139] c. x [018 12 27] and y = [ 12345]
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- Wirte a matlab code to plot the 3D image of a helix: Use the following parameters and equations that define the axes in 3D: p=0.199; Pitch distance (distance between the turns)a=0.02999500; Radius of the helis wireb=0.191; Radius of the helixn = 5, is the number of helis turns. δ = atan(p/(2*pi*b)); The pitch anglex’ = b + a cos(Ө)y’ = -a sin(Ө) sin(δ)x = x’ sin(ф)+y’ cos(ф);y =-x’ cos(ф)+y’ sin(ф);z = p*ф/(2*pi)+a*sin(Ө)*cos(δ);In Matlab. Attach code and plot screenshot.Please edit my MATLAB coding to include/fix the missing lines of coding that will satisfy the requirement of “Were both plots created on the same set of axes?”
- Use Matlab to Plot the graph shown in image 2 using data in table on image 1, BMI= W*H Where W is the weight in kilograms and H is the height in meters. Or the four color curves, use the line width ‘3’. To display a BMI of a person use the following: circular MarkSize ‘8’, MarkerEdgeColor ‘cyan’. To display this you have to enter two values. these are the Height in meters and Weight in kilograms. And inform the outcome results to the person from the command window.Need help with the question being ask for this MATLAB practice. Using version R2021b. Question/request is in the image for the following code. Need help with only 1a and 1b. I do not know how to type it out into matlab. Please help.Write MATLAB code that will plot the function x² - 10x + 25 over the x values 0 to 10 on a regular plot (use the command plot) using 21 evenly spaced points with the linspace command in one subplot and then for the second subplot, plot the same function over the x values 10-¹ to 10 ¹ using 21 evenly spaced points on a semi logarithmic plot (use the command semilogx). Put markers on each point used in the calculations (using a circle, x, or +, your choice) using a different marker and color for each plot, and include axis labels on each subplot. If the code is written correctly, your subplots should appear like the ones below. 25 y-axis 20 15 10 X 5 0 0 2 4 x-axis 6 8 10 25 PO 20 y-axis 15 10 5 0 10-1 O Copy/paste your code that will create the subplots in the text box below. 0 0 0 0 0 0 0 10⁰ x-axis 0 0 0 0 0 10¹
- The following is my code in MATLAB to transform kepler elements to cartesian coordinates. Can you give me the code of a function that will transform cartesian coordinates back to kepler elements that will match the inital kepler elements? mu = 3.986004415e5;a = 2.1656e03;ecc = 0.7404;inc = 123.8490;raan = 127.5686;argp = 180.0180;f = 180; R = orbitDCM(inc,raan,f+argp); %Create the direction cosine matrixp = a*(1-ecc^2); %Semi latus rectumh = sqrt(mu*p); %Orbital angular momentumrOrb = [p/(1+ecc*cosd(f));0;0]; %Position in orbital framevelOrb = [mu*ecc/h*sind(f);h/rOrb(1);0]; %Velocity in orbital framerxyz = R*rOrbvelxyz = R*velOrb function R = orbitDCM(inc,omeg,th)%Creates the direction cosine matrix for an orbit. The matrix can then%be used to convert between orbit frame coordinates (rhat,theta_hat,h_hat)%and inertial coordinates (x,y,z).R = eye(3);R(1,1) = cosd(omeg)*cosd(th)-sind(omeg)*cosd(inc)*sind(th);R(2,1) = sind(omeg)*cosd(th)+cosd(omeg)*cosd(inc)*sind(th);R(3,1) =…Plot y = cos x and z = 1- (x^2)/2 + (x^4)/24 on the same plot. And you can assume x values and then plot on matlabUse MATLAB MATLAB code only in the simplest form
- Use MATLAB to solve the imageIn Matlab, On a single page, type out an algorithm/pseudo-code that takes three 2D points as user input and outputs the geometric form that they make i.e. a point, a line or a triangle. The algorithm/pseudo-code should have 15-20 lines of text and no more than half of the lines should have code in them. The user should be asked for points consisting of integer x,y values and the algorithm should reject bad inputs.Q4/Full the following blanks (1101 1010)BCD(5211) = ( )BCD(3321)=()EX-3=()16 * (1101 1010)BCD(5211) = (1110 1100)BCD(3321)=(1010110)EX-3= (A6)16 (1101 1010)BCD(5211) = (1110 0111)BCD(3321)=(1011001)EX-3= (56)16 (1101 1010)BCD(5211) = (1101 0111)BCD(3321)=(1011001)EX-3= (2B)16 (1101 1010)BCD(5211) = (1011 1110)BCD(3321)=(1000111)EX-3= (44)16 None of them II