The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m=4The plaintext given by 10001001=x0x1x2x3x4x5x6x7 when encrypted by the LFSR produced the ciphertext 10110011=y0y1y2y3y3y5y6y7 What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3=0,p2=1,p1=0,p0=1

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Q: What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits

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Q: im not sure whats wrong

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