Construct and ICE table to find the value of Ke for the reaction. 2 CH (8) at 1700°C if the initial concentrations are (CH4lo 0.479 M. (C₂H₂lo Question 14 Calculate K, for each experiment for the reaction W = C₂H₂(g) + 3 H₂(g) 0.000M, [H₂lo 0.000M and the equilibrium (C₂Heleg-0.093 M. 2 NO₂(8) N₂O4(8) at 100°C, assuming (NO₂], 0.0200M, [N₂O4) = 0.0000M and [NO₂] = 0.0172M

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do both vey easy , if u plan to do only 1 then skip do both 

HANDWRITTING MUST BE GOOD , CLEAR IN A WHITE PAPER PLZZ ( or else dislike ) do both with clarity i will upvote

Question 13
Construct and ICE table to find the value of Ke for the reaction
2 CH4(8)
C₂H₂(g) + 3 H₂(g)
at 1700°C if the initial concentrations are [CH4], 0.479 M. [C₂H₂lo -0.000M, [H₂l. = 0.000M and the equilibrium (C₂H-leg-0.093 M.
Question 14
Calculate K, for each experiment for the reaction
2 NO₂(g) →→→→N₂O4(8)
at 100°C, assuming [NO₂), = 0.0200M, (N₂O4] =0.0000M and [NO2] = 0.0172M
4.7323
Transcribed Image Text:Question 13 Construct and ICE table to find the value of Ke for the reaction 2 CH4(8) C₂H₂(g) + 3 H₂(g) at 1700°C if the initial concentrations are [CH4], 0.479 M. [C₂H₂lo -0.000M, [H₂l. = 0.000M and the equilibrium (C₂H-leg-0.093 M. Question 14 Calculate K, for each experiment for the reaction 2 NO₂(g) →→→→N₂O4(8) at 100°C, assuming [NO₂), = 0.0200M, (N₂O4] =0.0000M and [NO2] = 0.0172M 4.7323
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