Consider two identical, finite, isolated systems of constant heat capacity C at temperatures T, and T2 (T> T:). An engine works between them until their temperatures become equal. Taking into account that the work performed by the engine will be maximum (= Wmax) if the process is reversible (equivalently, the entropy change of the entire system is zero). the value of Wmax is: Q.17 (A) C(T, - T2) (B) C (T – T2)/2 (C) C(T, + T2 - T;T2) 2 (D) C(/T, - VT2)
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