From the total differential for enthalpy, dH = TdS + VdP, one can solve for ds, then substitute dH = Cp (T) dT, to obtain a differential for S(T, P). ds Cp(T) T dT V 7dp This provides a means for evaluating entropy changes for processes from (P₁, T1) to (P2, T2). Use this formulation to evaluate AS for one mole of an ideal gas that starts with P₁ = 1.20 bar and T₁ = 242 K and ends with P₂ = 0.80 bar and T₂ = 373 K. Assume that Cp = 28 J/mol.K and is constant over this temperature range. Report AS in J/K. (Note: You will need to specify V(P).)
From the total differential for enthalpy, dH = TdS + VdP, one can solve for ds, then substitute dH = Cp (T) dT, to obtain a differential for S(T, P). ds Cp(T) T dT V 7dp This provides a means for evaluating entropy changes for processes from (P₁, T1) to (P2, T2). Use this formulation to evaluate AS for one mole of an ideal gas that starts with P₁ = 1.20 bar and T₁ = 242 K and ends with P₂ = 0.80 bar and T₂ = 373 K. Assume that Cp = 28 J/mol.K and is constant over this temperature range. Report AS in J/K. (Note: You will need to specify V(P).)
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Transcribed Image Text:From the total differential for enthalpy, dH = TdS + VdP, one can solve for ds, then
substitute dH = Cp (T) dT, to obtain a differential for S(T, P).
ds =
Cp(T)
T
dT
V
=dP
T
This provides a means for evaluating entropy changes for processes from (P₁, T₁) to (P2, T₂).
Use this formulation to evaluate AS for one mole of an ideal gas that starts with P₁ = 1.20 bar
and T₁ = 242 K and ends with P₂ = 0.80 bar and T₂ = 373 K. Assume that Cp = 28 J/mol-K and is
constant over this temperature range. Report AS in J/K. (Note: You will need to specify V(P).)
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