Consider the waveguideCalculate the phaseconstant, phase velocity and wave impedance for TE10 and TM11 modes at theoperating frequency of 15 GHz.Answer: For TE10, 6 = 615.6 rad/m, u = 1.531 × 108 m/s, TE = 192.4. ForTM11, B = 529.4 rad/m, u = 1.78 × 10° m/s, TM = 158.8 0.

Step 1: Step 2: Step 3: Step 4:

Answered: Consider the waveguide Calculate the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Find cut.off frequency.
3) Solve the cutoff frequency for the first mode and second mode of WR975 Wave guide TABLE 7.1 Some Standard Rectangular Waveguides Waveguide de signation a (in) b (in) t (in) fe, (GHz) Frequency range (GHz) WR975 9.750 4.875 0.125 0.605 0.75-1.12 WR650 6.500 3.250 0.080 0.908 1.12–1.70 WR430 4.300 2.150 0.080 1.375 1.70-2.60 WR284 2.840 1.340 0.080 2.08 2.60-3.95 WR187 1.872 0.872 0.064 3.16 3.95-5.85 WR137 1.372 0.622 0.064 4.29 5.85-8.20 WR90 0.900 0.450 0.050 6.56 8.2–12.4 WR62 0.622 0.311 0.040 9.49 12.4–18
Problem 5. We are transmitting our 12/4 APSK waveform with outer ring voltage 5 Volts and inner ring voltage = 2 Volts. The constellation ring ratio in dB is? a) 6.25 b) 7.959 c) 9.875 d) 9.945 e) 19.891
2) Find the first 4 modes of cut off frequency for the wave guide WR187.With the help of table given below.
4. Again, from the zigzag-path waveguiding model, explain why the group velocity is always slower than the phase velocity in a waveguide with a cutoff frequency.
An air- filled rectangular waveguide has dimensions of a 6 cm and b-4 cm. the signal frequency is 3 GHz. Compute the following for TE10, TE01, TE11 and TM₁1 modes. a- cutoff frequency. b- wavelength in the waveguide. c-phase constant and phase velocity in the waveguide.
a rectangular air-filled copper waveguide with dimension 2.28 cm x 1.01 cm across section and 30.48 cm length is operated at 9.2 GHz with a dominant mode. Find a)characteristic impedance b) attenuattion in dB
For the sinusoidal signal of 5 sin(wt) +10cos(wt) ; in the phase form of Aej(phi) ; where phi = tan-1(- (5/10)) ; why is negative included? shouldnt it be just tan-1(5/10)?
4.a. What's the typically acceptable maximum BER value in a multimode fiber?A. 10–7B. 10–6C. 10–9D. 10–84.b. What does a positive dBm value from a power meter tell you?A. The signal strength is less than 1 mW.B. The signal strength is greater than 1 mW.C. The signal strength is greater than 1 W.D. The signal strength is less than 1 W.
This is a practice question from Electronics Engineering, double sideband supressed carrier problem.
EXERCISE 1: Consider the waveguide of Example Calculate the phase constant, phase velocity and wave impedance for TE10 and TM11 modes at the operating frequency of 15 GHz. = 192.4 . For Answer: For TE10, B = 615.6 rad/m, u = 1.531 × 108 m/s, TE 529.4 rad/m, u = 1.78 x 10 m/s, TM = 158.8 Q. TM11, B Example 1: A rectangular waveguide with dimensions a = 2.5 cm, b = 1 cm is to operate below 15.1 GHz. How many TE and TM modes can the waveguide transmit? if the guide is filled with a medium characterized by σ = 0, &=4&o Hr = 1° Calculate the cutoff frequencies of the modes.
For a single-frequency sine wave modulating signal of 3 kHz with a carrier frequency of 36 MHz, what is the spacing between sidebands?

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Consider the waveguide Calculate the phase constant, phase velocity and wave impedance for TE10 and TM11 modes at the operating frequency of 15 GHz. Answer: For TE10, 6 = 615.6 rad/m, u = 1.531 × 108 m/s, TE = 192.4. For TM11, B = 529.4 rad/m, u = 1.78 × 10° m/s, TM = 158.8 0.