Consider the two bars of identical material with their elastic modulus E as shown in Figure below. Both bars have the same circular cross-section with diameter of d. The length of the longer bar is 2L and the length of the shorter bar is L. The angle between the bars is ß. The system is subjected to a vertical force acting at point P as shown in the figure with a magnitude of F. Calculate horizontal and vertical components of the displacement of point P. Use engineering notation (ENG display mode on scientific calculators) with 3 significant figures after the decimal point. E (psi) 1.50E+06 d (in) 1.25 L (in) 12 Beta (degrees) 30 F (Ibf) 110

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Consider the two bars of identical material with their elastic modulus E as shown in Figure
below. Both bars have the same circular cross-section with diameter of d. The length of the
longer bar is 2L and the length of the shorter bar is L. The angle between the bars is B. The
system is subjected to a vertical force acting at point Pas shown in the figure with a
magnitude of F. Calculate horizontal and vertical components of the displacement of point
P. Use engineering notation (ENG display mode on scientific calculators) with 3 significant
figures after the decimal point.
E (psi)
1.50E+06
d (in)
1.25
L (in)
12
Beta (degrees)
30
F (Ibf)
110
F P
L
2L
Transcribed Image Text:Consider the two bars of identical material with their elastic modulus E as shown in Figure below. Both bars have the same circular cross-section with diameter of d. The length of the longer bar is 2L and the length of the shorter bar is L. The angle between the bars is B. The system is subjected to a vertical force acting at point Pas shown in the figure with a magnitude of F. Calculate horizontal and vertical components of the displacement of point P. Use engineering notation (ENG display mode on scientific calculators) with 3 significant figures after the decimal point. E (psi) 1.50E+06 d (in) 1.25 L (in) 12 Beta (degrees) 30 F (Ibf) 110 F P L 2L
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