Consider the titration of 30.0 mL of 0.0700 M C2H5NH2 (a weak base; Kb = 0.000640) with 0.100 M HBrO4. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = (b) 5.3 mL pH = (c) 10.5 mL pH =
Consider the titration of 30.0 mL of 0.0700 M C2H5NH2 (a weak base; Kb = 0.000640) with 0.100 M HBrO4. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = (b) 5.3 mL pH = (c) 10.5 mL pH =
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the titration of 30.0 mL of 0.0700 M C2H5NH2 (a weak base; Kb = 0.000640) with 0.100 M HBrO4. Calculate the pH after the following volumes of titrant have been added:
(a) 0.0 mL pH =
(b) 5.3 mL pH =
(c) 10.5 mL pH =
(d) 15.8 mL pH =
(e) 21.0 mL pH =
(f) 27.3 mL pH =
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Step 1: Definition of Henderson-Hasselbalch equation.
VIEWStep 2: Given values.
VIEWStep 3: Calculation of pH at 0.0 mL.
VIEWStep 4: Calculation of pOH when 5.3 mL acid is added.
VIEWStep 5: Calculation of pH when 5.3 mL acid is added.
VIEWStep 6: Calculation of pOH when 10.5 mL acid is added.
VIEWStep 7: Calculation of pH when 10.5 mL acid is added.
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