Consider the titration of 20.0 mL of 0.0800 M C2H5NH2 (a weak base; Kb = 0.000640) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = (b) 4.0 mL pH = (c) 8.0 mL pH = (d) 12.0 mL pH = (e) 16.0 mL pH = (f) 19.2 mL pH =

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Consider the titration of 20.0 mL of 0.0800 M C2H5NH2 (a weak base; Kb = 0.000640) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = (b) 4.0 mL pH = (c) 8.0 mL pH = (d) 12.0 mL pH = (e) 16.0 mL pH = (f) 19.2 mL pH =

 

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