Consider the titration of 60.0 mL of 0.0400 M (CH3)2NH (a weak base; K = 0.000540) with 0.100 M HBrO4. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = 11.64 (d) 18.0 mL pH = 10.25 (b) 6.0 mL pH = 11.21 (e) 24.0 mL pH = X (c) 12.0 mL pH = 10.73 (f) 43.2 mL pH = X

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Consider the titration of 60.0 mL of 0.0400 M (CH3)2NH (a weak base; Kb = 0.000540) with 0.100 M HBrO4. Calculate the
pH after the following volumes of titrant have been added:
(a) 0.0 mL
pH = 11.64
(d) 18.0 mL
pH = 10.25
(b) 6.0 mL
pH = 11.21
(e) 24.0 mL
pH =
X
(c) 12.0 mL
pH = 10.73
(f) 43.2 mL
pH =
X
Transcribed Image Text:Consider the titration of 60.0 mL of 0.0400 M (CH3)2NH (a weak base; Kb = 0.000540) with 0.100 M HBrO4. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL pH = 11.64 (d) 18.0 mL pH = 10.25 (b) 6.0 mL pH = 11.21 (e) 24.0 mL pH = X (c) 12.0 mL pH = 10.73 (f) 43.2 mL pH = X
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