Consider the following reaction mechanism. If this mechanism is correct, and ki is much smaller than k2, then the observed rate law would be: ki 2 A C + I k2 I + B C + D

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
**Reaction Mechanism Explanation:**

Consider the following reaction mechanism. If this mechanism is correct, and \( k_1 \) is much smaller than \( k_2 \), then the observed rate law would be:

1. **Reaction Step 1:** 

   \[
   2A \xrightarrow{k_1} C + I
   \]

2. **Reaction Step 2:**

   \[
   I + B \xrightarrow{k_2} C + D
   \]

**Choices for the Observed Rate Law:**

- \( R = k_1 [A]^2 \)
- \( R = k_1 k_2 [A]^2 [I] [B] \)
- \( R = k_1 [A]^2 - k_2 [C] [D] \)
- \( R = k_1 [A] \)
- \( R = k_2 [I] [B] \)

**Explanation:**

The mechanism consists of two steps. In the first step, two molecules of A react to give species C and an intermediate I, with the rate constant \( k_1 \). In the second step, the intermediate I reacts with B to produce species C and D, with the rate constant \( k_2 \).

Since \( k_1 \) is much smaller than \( k_2 \), the first step is likely the rate-determining step. The observed rate law will depend on the concentration of reactants involved in this slowest step.
Transcribed Image Text:**Reaction Mechanism Explanation:** Consider the following reaction mechanism. If this mechanism is correct, and \( k_1 \) is much smaller than \( k_2 \), then the observed rate law would be: 1. **Reaction Step 1:** \[ 2A \xrightarrow{k_1} C + I \] 2. **Reaction Step 2:** \[ I + B \xrightarrow{k_2} C + D \] **Choices for the Observed Rate Law:** - \( R = k_1 [A]^2 \) - \( R = k_1 k_2 [A]^2 [I] [B] \) - \( R = k_1 [A]^2 - k_2 [C] [D] \) - \( R = k_1 [A] \) - \( R = k_2 [I] [B] \) **Explanation:** The mechanism consists of two steps. In the first step, two molecules of A react to give species C and an intermediate I, with the rate constant \( k_1 \). In the second step, the intermediate I reacts with B to produce species C and D, with the rate constant \( k_2 \). Since \( k_1 \) is much smaller than \( k_2 \), the first step is likely the rate-determining step. The observed rate law will depend on the concentration of reactants involved in this slowest step.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Rate Laws
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY