Consider the following RC circuit, what are values of V (+∞) and Vc (0)? Vo t=0 R V C ic

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Hint: when t<0, the switch is closed, and the switch will be opened at t=0. For t>0, the switch
remains open. Let us travel the time axis to analyze this circuit:
8118
Switch is closed
Switch is closed
Switch is open
t=0 t = 0+
t=0
t=48
Switch is open
First, at t=-∞, the switch is closed, and the voltage source Vo begins to charge the capacitor C.
Next, consider t=0, which is the time step just before t=0. At this moment, the switch is still
closed since we have not reached t=0 yet. Besides, the capacitor C is fully charged, and its voltage
is stabilized. In this case, the capacitor is equivalent to an open circuit, i.e., ic = 0.
Then, consider t=0+, which is the time instant immediately after t=0. At this time, the switch is
open. One important feature of capacitors is that the voltage on a capacitor can't be suddenly
changed, i.e., the voltage on a capacitor is a continuous value. Thus, Vc (0+) = Vc (0¯).
Finally, consider t=+∞. After disconnecting from the voltage source for a long time, the energy
stored inside the capacitor is all dissipated.
O Ve (0) = Voi V₂ (+∞o) = 0
O Ve (0) = 0; Ve(+∞o) = Vo
O Ve (0)=ie C; Vc (+∞0) = 0
O Ve (0) = Voi Ve (+00) = in R
Transcribed Image Text:Hint: when t<0, the switch is closed, and the switch will be opened at t=0. For t>0, the switch remains open. Let us travel the time axis to analyze this circuit: 8118 Switch is closed Switch is closed Switch is open t=0 t = 0+ t=0 t=48 Switch is open First, at t=-∞, the switch is closed, and the voltage source Vo begins to charge the capacitor C. Next, consider t=0, which is the time step just before t=0. At this moment, the switch is still closed since we have not reached t=0 yet. Besides, the capacitor C is fully charged, and its voltage is stabilized. In this case, the capacitor is equivalent to an open circuit, i.e., ic = 0. Then, consider t=0+, which is the time instant immediately after t=0. At this time, the switch is open. One important feature of capacitors is that the voltage on a capacitor can't be suddenly changed, i.e., the voltage on a capacitor is a continuous value. Thus, Vc (0+) = Vc (0¯). Finally, consider t=+∞. After disconnecting from the voltage source for a long time, the energy stored inside the capacitor is all dissipated. O Ve (0) = Voi V₂ (+∞o) = 0 O Ve (0) = 0; Ve(+∞o) = Vo O Ve (0)=ie C; Vc (+∞0) = 0 O Ve (0) = Voi Ve (+00) = in R
For an RC circuit (RC stands for Resistor and Capacitor), the voltage on the capacitor follows
this expression:
Vc (t) = K₁ + K₂ e , T = R.C
·
where K₁ = Vc (+00), K₁1 + K₂ = Vc (0).
To find V. (t), we need to figure out what values of Ve (+) and Vc (0) are, then, we can
solve for K₁ and K₂.
Consider the following RC circuit, what are values of V (+∞) and Vc (0)?
+
t = 0
Switch is closed
t=0
Hint: when t<0, the switch is closed, and the switch will be opened at t=0. For t>0, the switch
remains open. Let us travel the time axis to analyze this circuit:
+
Ry – С
ic
Switch is open
t = 0
Transcribed Image Text:For an RC circuit (RC stands for Resistor and Capacitor), the voltage on the capacitor follows this expression: Vc (t) = K₁ + K₂ e , T = R.C · where K₁ = Vc (+00), K₁1 + K₂ = Vc (0). To find V. (t), we need to figure out what values of Ve (+) and Vc (0) are, then, we can solve for K₁ and K₂. Consider the following RC circuit, what are values of V (+∞) and Vc (0)? + t = 0 Switch is closed t=0 Hint: when t<0, the switch is closed, and the switch will be opened at t=0. For t>0, the switch remains open. Let us travel the time axis to analyze this circuit: + Ry – С ic Switch is open t = 0
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