Consider the following method for the analysis of cocaine (MW 303.35) powder. "Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of glacial acetic acid, add I drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS to a green endpoint. Perform a blank determination, and make the necessary correction" Calculate the percentage purity of the cocaine sample from the data below. Show your reasoning clearly and record your final answer to four significant figures. Cocaine powder weighed = 606.3 mg Concentration of HCIO3 = 0.09978 M H₂C-N Volume HCIO3 required for the assay mixture = 19.97 mL Volume HCIO3 required for blank determination = 0.059'mL ●

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Chapter1: Chemical Foundations
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Consider the following method for the analysis of cocaine (MW 303.35) powder.
"Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of
glacial acetic acid, add I drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS
to a green endpoint. Perform a blank determination, and make the necessary correction"
Calculate the percentage purity of the cocaine sample from the data below. Show your
reasoning clearly and record your final answer to four significant figures.
CH₂
●
Cocaine powder weighed = 606.3 mg
Concentration of HCIO3=0.09978 M
H₂C-N-
Volume HCIO3 required for the assay mixture = 19.97 mL
●
Volume HCIO; required for blank determination = 0.059'mL
Transcribed Image Text:Consider the following method for the analysis of cocaine (MW 303.35) powder. "Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of glacial acetic acid, add I drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS to a green endpoint. Perform a blank determination, and make the necessary correction" Calculate the percentage purity of the cocaine sample from the data below. Show your reasoning clearly and record your final answer to four significant figures. CH₂ ● Cocaine powder weighed = 606.3 mg Concentration of HCIO3=0.09978 M H₂C-N- Volume HCIO3 required for the assay mixture = 19.97 mL ● Volume HCIO; required for blank determination = 0.059'mL
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