A batch of codeine phosphate powder was analysed according to the BP (1999) method described below. "Dissolve 0.350 g in a mixture of 10 mL anhydrous acetic acid and 20 mL of 1,4-dioxan R. Titrate with 0.1 M perchloric acid (MM 100.46 g/mol) using 0.05 mL of crystal violet solution R as indicator." The following results were obtained: Weight of powder taken for analysis 0.3495 g 8.53 mL Volume of 0.1 M HCIO, required to neutralise the base Concentration of HCIO4 = = 0.09923 M Calculate the percentage purity of codeine phosphate. Explain your reasoning clearly
A batch of codeine phosphate powder was analysed according to the BP (1999) method described below. "Dissolve 0.350 g in a mixture of 10 mL anhydrous acetic acid and 20 mL of 1,4-dioxan R. Titrate with 0.1 M perchloric acid (MM 100.46 g/mol) using 0.05 mL of crystal violet solution R as indicator." The following results were obtained: Weight of powder taken for analysis 0.3495 g 8.53 mL Volume of 0.1 M HCIO, required to neutralise the base Concentration of HCIO4 = = 0.09923 M Calculate the percentage purity of codeine phosphate. Explain your reasoning clearly
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![PEY
FOS
A batch of codeine phosphate powder was analysed according to the BP (1999) method
described below.
"Dissolve 0.350 g in a mixture of 10 mL anhydrous acetic acid and 20 mL of 1,4-dioxan
R. Titrate with 0.1 M perchloric acid (MM 100.46 g/mol) using 0.05 mL of crystal violet
solution R as indicator."
The following results were obtained:
Weight of powder taken for analysis
= 0.3495 g
= 8.53 mL
Volume of 0.1 M HClO4 required to neutralise the base
Concentration of HCIO4
= 0.09923 M
Calculate the percentage purity of codeine phosphate. Explain your reasoning clearly.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F122eb431-f16a-43cb-8178-a9349a632f30%2F4d11082a-1fe4-4696-801f-1f6475eca052%2Fo1xok76_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PEY
FOS
A batch of codeine phosphate powder was analysed according to the BP (1999) method
described below.
"Dissolve 0.350 g in a mixture of 10 mL anhydrous acetic acid and 20 mL of 1,4-dioxan
R. Titrate with 0.1 M perchloric acid (MM 100.46 g/mol) using 0.05 mL of crystal violet
solution R as indicator."
The following results were obtained:
Weight of powder taken for analysis
= 0.3495 g
= 8.53 mL
Volume of 0.1 M HClO4 required to neutralise the base
Concentration of HCIO4
= 0.09923 M
Calculate the percentage purity of codeine phosphate. Explain your reasoning clearly.
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