Consider the classes base and derived as follows. class base { protected:      virtual void step_one() {std::cout << "base::step_one" << std::endl;}      virtual void step_two() {std::cout << "base::step_two" << std::endl;} public:      void run() {           std::cout << "enter base::run" << std::endl;           step_one();           step_two();           std::cout << "exit base::run" << std::endl; } }; class derived : public base { protected:      void step_one() {std::cout << "derived::step_one" << std::endl;}      void step_two() {std::cout << "derived::step_two" << std::endl;} public:      void run() {           std::cout << "enter derived::run" << std::endl;           step_one();           step_two();           std::cout << "exit derived::run" << std::endl; } }; A. What’s the output of the following function test1? void test1() {      derived d;      derived *p = &d;      p->run(); } B. What’s the output of the following function test2? void test2() {      derived d;      base *p = &d;      p->run(); }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question

Consider the classes base and derived as follows.


class base {
protected:
     virtual void step_one() {std::cout << "base::step_one" << std::endl;}
     virtual void step_two() {std::cout << "base::step_two" << std::endl;}
public:
     void run() {
          std::cout << "enter base::run" << std::endl;
          step_one();
          step_two();
          std::cout << "exit base::run" << std::endl;
}
};

class derived : public base {
protected:
     void step_one() {std::cout << "derived::step_one" << std::endl;}
     void step_two() {std::cout << "derived::step_two" << std::endl;}
public:
     void run() {

          std::cout << "enter derived::run" << std::endl;
          step_one();
          step_two();
          std::cout << "exit derived::run" << std::endl;
}
};


A. What’s the output of the following function test1?
void test1() {
     derived d;
     derived *p = &d;
     p->run();
}


B. What’s the output of the following function test2?
void test2() {
     derived d;
     base *p = &d;
     p->run();
}

Expert Solution
Step 1

In the first question 1, first an object of class dervied is created and then a pointer of type derived is created.

This pointer is pointing to the location of the derived class object.

 

Using the above pointer, the function run() of the derived class is called. The Derived class's step_one() and step_two() functions are also called within the function.

 

Thus, the output will be:

enter derived::run

derived::step_one

derived::step_two
          
exit derived::run

 

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