Consider the circuit shown in the figure below. (Assume R1 = 12.0 Ω, R2 = 3.70 Ω, and V = 7.10 V.) A rectangular circuit begins at the positive terminal of a battery labeled V, which is on the bottom side of the rectangle. The circuit extends up and to the left to resistor labeled R2 on the top side of the rectangle. To the right of R2 the circuit splits into two parallel horizontal branches. The top branch splits into two parallel horizontal sub-branches. There is a resistor labeled R1 on the top sub-branch and a 5.00 Ω resistor on the bottom sub-branch. The sub-branches then recombine and the top branch extends to the right to a 4.00 Ωresistor. The bottom branch contains a 3.00 Ω resistor. The top and bottom branches then recombine and the circuit extends down and to the left until it reaches the negative terminal of the battery. (a) Calculate the equivalent resistance of the R1 and 5.00-Ω resistors connected in parallel. Ω (b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-Ω and 4.00-Ω resistors. Ω (c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-Ω resistor. Ω (d) Combine the equivalent resistance found in part (c) with the R2 resistor. Ω (e) Calculate the total current in the circuit. A (f) What is the voltage drop across the R2 resistor? V (g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-Ω resistor. V (h) Calculate the current in the 3.00-Ω resistor. A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Consider the circuit shown in the figure below. (Assume R₁ = 12.0 Ω, R₂ = 3.70 Ω, and V = 7.10 V.)

A rectangular circuit begins at the positive terminal of a battery labeled V, which is on the bottom side of the rectangle. The circuit extends up and to the left to resistor labeled R₂ on the top side of the rectangle. To the right of R₂ the circuit splits into two parallel horizontal branches.

The top branch splits into two parallel horizontal sub-branches. There is a resistor labeled R₁ on the top sub-branch and a 5.00 Ω resistor on the bottom sub-branch. The sub-branches then recombine and the top branch extends to the right to a 4.00 Ωresistor.
The bottom branch contains a 3.00 Ω resistor.

The top and bottom branches then recombine and the circuit extends down and to the left until it reaches the negative terminal of the battery.

(a) Calculate the equivalent resistance of the R₁ and 5.00-Ω resistors connected in parallel.
Ω

(b) Using the result of part (a), calculate the combined resistance of the R₁, 5.00-Ω and 4.00-Ω resistors.
Ω

(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-Ω resistor.
Ω

(d) Combine the equivalent resistance found in part (c) with the R₂ resistor.
Ω

(e) Calculate the total current in the circuit.
A

(f) What is the voltage drop across the R₂ resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-Ω resistor.
V

(h) Calculate the current in the 3.00-Ω resistor.
A

R₂
R₁
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5.00 Ω
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4.00 Ω
3.00 Ω
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