An open circuit containing five resistors starts at point a and ends at point b. The circuit extends to the right from point a and splits into two parallel horizontal branches. There is a 12.0 Ω resistor on the top branch and a 6.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right to a 5.00 Ω resistor. To the right of the 5.00 Ω resistor, the circuit again splits into two parallel horizontal branches. There is a 4.00 Ω resistor on the top branch and an 8.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right until it reaches point b
An open circuit containing five resistors starts at point a and ends at point b. The circuit extends to the right from point a and splits into two parallel horizontal branches. There is a 12.0 Ω resistor on the top branch and a 6.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right to a 5.00 Ω resistor. To the right of the 5.00 Ω resistor, the circuit again splits into two parallel horizontal branches. There is a 4.00 Ω resistor on the top branch and an 8.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right until it reaches point b.
Given
Total 5 resistors ,
R1 = 12.0 ohm
R2 = 6.0 ohm
R3 = 5.0 ohm
R4 = 4.0 ohm
R5 = 8.0 ohm
Step by step
Solved in 3 steps with 2 images
