An open circuit containing five resistors starts at point a and ends at point b. The circuit extends to the right from point a and splits into two parallel horizontal branches. There is a 12.0 Ω resistor on the top branch and a 6.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right to a 5.00 Ω resistor. To the right of the 5.00 Ω resistor, the circuit again splits into two parallel horizontal branches. There is a 4.00 Ω resistor on the top branch and an 8.00 Ω resistor on the bottom branch. The branches then recombine and the circuit extends to the right until it reaches point b.
(b) If a voltage of 50 V is applied between points a and b, find the current in each resistor.
12 Ω | ?A |
6 Ω | ?A |
5 Ω | ? A |
4 Ω | ? A |
8 Ω | ? A |
Given
R1 = 12 ohm
R2 = 6 ohm
R3 = 5 ohm
R4 = 4 ohm
R5 = 8 ohm
Step by step
Solved in 4 steps with 2 images