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Consider a p-n junction at room temperature. Doping concentration in the n and p regions is Np = 1-1017 cm 3 and NA = 4-1017 cm 3, respectively. Calculate the position of the Fermi energy level in the p-type semiconductor relative to the valence band edge. Give your answer in eV. If needed, use the following values for material parameters: Nc = 2.8· 1019 cm 3 Ny = 10.1019 cm 3 n; = 1.5 1010 cm-3 %3D kT = 26 meV EG = 1.1 ev %3! Your Answer: Answer units

Consider a p-n junction at room temperature. Doping concentration in the n and p regions is Np = 1-1017 cm 3 and NA = 4-1017 cm 3, respectively. Calculate the position of the Fermi energy level in the p-type semiconductor relative to the valence band edge. Give your answer in eV. If needed, use the following values for material parameters: Nc = 2.8· 1019 cm 3 Ny = 10.1019 cm 3 n; = 1.5 1010 cm-3 %3D kT = 26 meV EG = 1.1 ev %3! Your Answer: Answer units

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Consider a p-n junction at room temperature. Doping concentration in the n and p regions is Np = 1-1017 cm 3 and NA = 4-1017 cm 3, respectively. Calculate the position of the Fermi energy level in the p-type semiconductor relative to the valence band edge. Give your answer in eV. If needed, use the following values for material parameters: Nc = 2.8 - 1019 cm 3 Ny = 10 1019 cm-3 %3D n; = 1.5 1010 cm-3 %3D kT = 26 meV EG = 1.1 ev Your Answer: Answer units
Transcribed Image Text:Consider a p-n junction at room temperature. Doping concentration in the n and p regions is Np = 1-1017 cm 3 and NA = 4-1017 cm 3, respectively. Calculate the position of the Fermi energy level in the p-type semiconductor relative to the valence band edge. Give your answer in eV. If needed, use the following values for material parameters: Nc = 2.8 - 1019 cm 3 Ny = 10 1019 cm-3 %3D n; = 1.5 1010 cm-3 %3D kT = 26 meV EG = 1.1 ev Your Answer: Answer units
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