Consider a genome whose length is 1000 bp. "Shotgun" sequencing techniques are applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20×50 = 1000, there is no guarantee that ALL 1000 bp of the genome are represented in the fragments. Calculate the coverage. What does this value mean? Why would it be a good idea to have a coverage greater than 1? Objective: Get a sense of how genomics, the study of the genome in its entirety,needs to think about how to go about its research.Geonomic DNA is broken up into fragments. The 5' and 3' ends of each fragment(a "read") are sequenced. The sequenced reads are assembled together intocontiguous sequences (“contigs") based on sequence similarity.The idea is to sequence enough random fragments so that every nucleotide in thegenome is represented on some read. The number of such fragments needed iscalled the coverage, c.The coverage c can be calculated by the formula RL/G, where R is the number ofreads sequenced, L is the average length of a read and G is the total length of thegenome. The units of length are bases (b) or base pairs (bp).1. Consider a genome whose length is 1000 bp. "Shotgun" sequencing techniquesare applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20 × 50 1000, there is no guaranteethat ALL 1000 bp of the genome are represented in the fragments. Calculate thecoverage. What does this value mean?

Shotgun sequencing is an important tool in modern genomics that allows researchers to interpret the…

Consider a genome whose length is 1000 bp. "Shotgun" sequencing techniques are applied to the genome, resulting in 20 reads, with an average length of 50 bp. A very important point is that, even though 20×50 = 1000, there is no guarantee that ALL 1000 bp of the genome are represented in the fragments. Calculate the coverage. What does this value mean? Why would it be a good idea to have a coverage greater than 1?

Consider a genome whose length is 1000 bp. "Shotgun" sequencing techniques are applied to the genome, resulting in 20 reads, with an average length of 50 bp. A very important point is that, even though 20×50 = 1000, there is no guarantee that ALL 1000 bp of the genome are represented in the fragments. Calculate the coverage. What does this value mean? Why would it be a good idea to have a coverage greater than 1?

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 6QP: Which of the following best describes the process of DNA sequencing? a. DNA is separated on a gel,...

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Objective: Get a sense of how genomics, the study of the genome in its entirety,needs to think about how to go about its research. Geonomic DNA is broken up into fragments. The 5’ and 3’ ends of each fragment(a “read”) are sequenced. The sequenced reads are assembled together intocontiguous sequences (“contigs”) based on sequence similarity. The idea is to sequence enough random fragments so that every nucleotide in thegenome is represented on some read. The number of such fragments needed iscalled the coverage, c. The coverage c can be calculated by the formula RL/G, where R is the number ofreads sequenced, L is the average length of a read and G is the total length of thegenome. The units of length are bases (b) or base pairs (bp). Consider a genome whose length is 1000 bp. “Shotgun” sequencing techniquesare applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20 x 50 = 1000, there is no guaranteethat ALL…
Objective: Get a sense of how genomics, the study of the genome in its entirety,needs to think about how to go about its research. Geonomic DNA is broken up into fragments. The 5’ and 3’ ends of each fragment(a “read”) are sequenced. The sequenced reads are assembled together intocontiguous sequences (“contigs”) based on sequence similarity. The idea is to sequence enough random fragments so that every nucleotide in thegenome is represented on some read. The number of such fragments needed iscalled the coverage, c. The coverage c can be calculated by the formula RL/G, where R is the number ofreads sequenced, L is the average length of a read and G is the total length of thegenome. The units of length are bases (b) or base pairs (bp). Consider a genome whose length is 1000 bp. “Shotgun” sequencing techniquesare applied to the genome, resulting in 20 reads, with an average length of 50 bp.A very important point is that, even though 20 x 50 = 1000, there is no guaranteethat ALL…
Genetic Engineering Terms Name: Draw a line to connect each pair of boxes DNA sequencing The use of an organism, or a component of an organism or other biological system, to make a product or process. DNA cloning The sequencing, analysis, and cutting-and-pasting of DNA A technique to make many copies of a specific DNA region in vitro (in a test tube rather than anorganism) Recombinant DNA Polymerase chain reaction A technique used.to separatę DNA fragments according to their size Gel electrophoresis DNA that is assembled out of fragments from multiple sources Biotechnology A molecular biology technique that makes many identical copies of a piece of DNA, such as a gene DNA technology The process of determining the sequence of nucleotides (As, Ts, Cs, and Gs) in a piece of DNA. ww tİ6111749/enetic-engineering-tems
Genomic sequencing cannot be used to: Predict a protein coding gene Predict structure and function of a protein encoded in a gene Locate similar sequences (sequence homology) Locate repetitive sequences Predicting alternative splicing patterns
Genomics and proteomics give us insights into genome function. True False
Which of the following is NOT an activity carried out in the field of bioinformatics? a. collecting and storing DNA sequence information produced by various genome sequencing projects b. analyzing genome sequences to determine the location of genes c. determining the three-dimensional structure of proteins d. comparing genomes of different species e. none of these
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