Component Acetone Initial mass fraction is 0.50 for each component. compositions of water, acetone, MIBK Mass Fractions (Raffinate) Mass Fractions (MIBK) MIBK Water Stream 1 mass raffinate 0.10 0.15 0.70 Stream 2 mass (extract) Calc Mass of MIBK Phase added Raffinate H₂0 = 0.70 Acetone = 0.10 MIBK = 0.15. 192.0 0.25 0.70 0.05 Extract Acetone 0.25, MIBK = 0.70 = 0.05 H20 = kg acetone F = 280 water mixture Initial mass fraction is 0.50 for each conConent. Nitial 0.50 3.50 Acetone 95 90 85 30 m3 + 280 = ME Ace Balance: 0,5,280 = 0.22 ME +0. Heo Balance: 0.5.280 = 0.25 ME +0.74 H₂O Region B initial Region A 50% 150% R ✓ ✓ 60- 55- a -45- 25 190= 0.22ME 190-0.50 E 190 10. 0 190=0 MIBK દ ME: { Three-phase diagram: The large dot on the left axis of the 3-compnent phase diagram represents the initial condition of a 280 kg acetone/water mixture, composed of 0.50 mass fraction of each component. A water-immiscible MIBK (methyl isobutyl ketone) solvent is added and mixed well with the acetone/water mixture, and then allowed to separate into two liquid phases. The overall composition of the entire liquid system after the MIBK addition is denoted by the large dot in the middle of the two-phase region. Use the tie line associated with the middle dot to determine the acetone / MIBK / H₂O compositions (fill in the blanks in the table) of the two final phases (raffinate (left side) and extract(right side)). Calculate then the masses of the two final phases. Once you have determined those two masses, calculate the mass of the MIBK phase which was added to the initial 280 kg mixture to give the two phase system. Il in table below to give the compositions of the two streams. Mass fractions in water-rich phase Mass fractions in MIBK-rich phase extractant (right))
Component Acetone Initial mass fraction is 0.50 for each component. compositions of water, acetone, MIBK Mass Fractions (Raffinate) Mass Fractions (MIBK) MIBK Water Stream 1 mass raffinate 0.10 0.15 0.70 Stream 2 mass (extract) Calc Mass of MIBK Phase added Raffinate H₂0 = 0.70 Acetone = 0.10 MIBK = 0.15. 192.0 0.25 0.70 0.05 Extract Acetone 0.25, MIBK = 0.70 = 0.05 H20 = kg acetone F = 280 water mixture Initial mass fraction is 0.50 for each conConent. Nitial 0.50 3.50 Acetone 95 90 85 30 m3 + 280 = ME Ace Balance: 0,5,280 = 0.22 ME +0. Heo Balance: 0.5.280 = 0.25 ME +0.74 H₂O Region B initial Region A 50% 150% R ✓ ✓ 60- 55- a -45- 25 190= 0.22ME 190-0.50 E 190 10. 0 190=0 MIBK દ ME: { Three-phase diagram: The large dot on the left axis of the 3-compnent phase diagram represents the initial condition of a 280 kg acetone/water mixture, composed of 0.50 mass fraction of each component. A water-immiscible MIBK (methyl isobutyl ketone) solvent is added and mixed well with the acetone/water mixture, and then allowed to separate into two liquid phases. The overall composition of the entire liquid system after the MIBK addition is denoted by the large dot in the middle of the two-phase region. Use the tie line associated with the middle dot to determine the acetone / MIBK / H₂O compositions (fill in the blanks in the table) of the two final phases (raffinate (left side) and extract(right side)). Calculate then the masses of the two final phases. Once you have determined those two masses, calculate the mass of the MIBK phase which was added to the initial 280 kg mixture to give the two phase system. Il in table below to give the compositions of the two streams. Mass fractions in water-rich phase Mass fractions in MIBK-rich phase extractant (right))
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Please need help.... i have tried to interpret graph. need mass of mibk and extract.
Transcribed Image Text:Component
Acetone
Initial mass fraction is 0.50 for each component.
compositions of water, acetone, MIBK
Mass Fractions (Raffinate)
Mass Fractions (MIBK)
MIBK
Water
Stream 1 mass raffinate
0.10
0.15
0.70
Stream 2 mass (extract)
Calc Mass of MIBK Phase added
Raffinate
H₂0 = 0.70
Acetone = 0.10
MIBK = 0.15.
192.0
0.25
0.70
0.05
Extract
Acetone 0.25, MIBK = 0.70
= 0.05
H20 =
kg acetone
F = 280
water mixture
Initial mass fraction is 0.50 for each conConent.
Nitial
0.50
3.50
Acetone
95
90
85
30
m3 + 280 = ME
Ace Balance: 0,5,280 = 0.22 ME +0.
Heo Balance: 0.5.280 = 0.25 ME +0.74
H₂O
Region B
initial
Region A
50% 150%
R
✓ ✓ 60-
55-
a
-45-
25
190= 0.22ME
190-0.50
E
190
10.
0
190=0
MIBK
દ
Transcribed Image Text:ME:
{
Three-phase diagram: The large dot on the left axis of the 3-compnent phase
diagram represents the initial condition of a 280 kg acetone/water mixture, composed of
0.50 mass fraction of each component. A water-immiscible MIBK (methyl isobutyl ketone)
solvent is added and mixed well with the acetone/water mixture, and then allowed to
separate into two liquid phases. The overall composition of the entire liquid system after
the MIBK addition is denoted by the large dot in the middle of the two-phase region. Use
the tie line associated with the middle dot to determine the acetone / MIBK / H₂O
compositions (fill in the blanks in the table) of the two final phases (raffinate (left side) and
extract(right side)). Calculate then the masses of the two final phases. Once you have
determined those two masses, calculate the mass of the MIBK phase which was added to
the initial 280 kg mixture to give the two phase system.
Il in table below to give the compositions of the two streams.
Mass fractions in water-rich phase
Mass fractions in MIBK-rich phase
extractant (right))
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