(Civil Engineering Surveying) Topic Lesson: "Route Surveying: Horizontal Curve" Sample Problem Situation: The tangents of a simple curve have bearings of N 20° E and N 80° E respectively. The radius of the curve is 200m. Question 1.) Compute the external distance of the curve.

Q: Compute the passing sight distance available given a 435-ft curve, grades of g₁=+2.00% and 92 =…

A: Curve length, L = 435 fth1 = 3.25 fth2 = 4.50 ftg1 = 2 %g2 = -1.5 %VPI at station 96+80Elevation =…

Q: Compute the radius of horizontal circular curve if you know the station of PC (25+24.23) and station…

A: A vertical curve is provided at a point where two straight lines at different gradients intersect in…

Q: Problem #6 A reverse horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

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Q: Problem #5 A compound horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

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Q: (Civil Engineering Surveying) Topic Lesson: "Route Surveying: Horizontal Curve" Sample Problem…

A: Given data  R = 200 m  Tangent 1 :- N20°E  Tangent 2 :- N80°E

Q: Part A Compute the stopping sight distance available given a 520-ft curve, grades of 91 = +2.00% and…

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Q: The long chord from the P.C to the P.T of a compound curve is 270.94 meters long and the angles its…

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Q: Example 3: Try This In Your Own......... The tangent distance of a simple curve is 94.963m and its…

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Q: answer all parts

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Q: Write the concept of curve fitting briefly

A: The process of creating a curve, or mathematical function, that has the best fit to a set of data…

Q: A 5º73' simple curve having a central angle of 57037' is situated along the steep side of Mount…

A: Note: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question…

Q: Šituation: Simple curve connects two tangents XY and YZ The survey data are the following: Bearing…

A: Station of Point of curvature, PC =4+288.4Station of point of intersection, PI =4+360.2Tangent…

Q: PC1 PI1 0+000 Lct PT1 R1 11 STATION NORTHINGS EASTINGS 0+000 11475.55 8927.24 PC2 9291.91 9546.66…

A: To Determine Table 3 ( The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of Project)…

Q: Compute the distance (in meter, along the curve) from P.C. to P.T. of the compound curve given: I, =…

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Q: Same situation as provided in the question in the image shared. Suppose the spiral curve is…

A: Given data: Length of the spiral curve=230 ft Normal crown rate = 2.5% Design Speed, V = 50 mph…

Q: The common tangent AB of a compound curve is 76.42-m, with an azimuth of 88°30'. The vertex V being…

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Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

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Q: 1. Horizontal Curve Given Pl at 3+333.013, A=12°47', and R = 300m, compute the cumulative…

A: Find the tangent,T=Rtan∆2=300tan12°47'2=33.605mConvert the tangent deflection…

Q: Engineering Surveys: Determine the radius of the central curve in a spiral curve if the angle of…

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Q: 1. A reverse curve has the following properties: Degree of curve, D₁ = 3⁰ Central angle, 1₁ = 24⁰…

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Q: 3. In laying out a simple curve using deflection angle method, given are: D = 10.50 (deg), I = 55…

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Q: One of the horizontal curve aside from Simple, compound, and reverse curves that were presented in…

A: 1. A spiral curve is curve whose radius is gradually increasing which helps in smooth transition…

Q: Given the following elements of a typical compound curve: Angle of intersection (I1) = 21°20'…

A: Given Angle of intersection (I1) = 21°20' Angle of intersection (I2) = 30°02' Degree of 1 curve (D1)…

Q: Civil Engineering Surveying) Topic Lesson: "Route Surveying: Horizontal Curve" Sample Problem…

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Q: Q4) For the horizo point of curvature (12+04.018). Calculate:- 1- All the elements of the horizontal…

A: Data given:Deflection angle = 31ο24'Point of tangent (T2) = 15+08Point of curvature (T1) =…

Q: The tangents of a simple curve have bearings of N 21° E and N 72° E, respectively. The degree of the…

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Q: Compute the first three entries in a table for setting out the following vertical curve, at…

A: Given data: Incoming slope = 1.8 = g1 Outgoing slope = -1.2 = g2 RL = 300M

Q: lations & Drawings QI/ Connect the tangents shown in the fig. with simple circular curve and…

A: Given Intersection angle, I = 50° Degree of curve, D = 2° To Determine L, R T, M

Q: Practical part: Q1). It is required to connect two intersecting straights whose deflection angle is…

A: The given data is shown below: Deflection angle=39°18'30''Radius=600m

Q: See Laboratory 5 Specific Information sheet for the Crew Assigned Station and Curve Elements. Given…

A: Answer  Calculation of Tangent 'T' Tangent 'T' is given by T = R*tan∆2 Radius R = 61.00 ft…

Q: Seatwork. A simple curve is to be laid out by deflection angle method with the following field data:…

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Q: A vertical summit curve has a backward tangent of+5% and a forward tangent of -8%,what is the…

A: Given:- The grade of the backward tangent = +5% The grade of the forward tangent = -8% The length of…

Q: GIVEN: The bearings of two tangents are S15°20'E and N23°17'E. If the degree of curve is 20° for a…

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Q: 1. Compute the degree of curve of a simple curve having a perpendicular distance from the tangent to…

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Q: IV. Calculation Patan Numbar) • Ic, = 2Rsin(a,/2) • x, = le,cos(a,/2) % = le,sin(a,/2) V. Data and…

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Q: Horizontal highway curve: Given PI at 95 + 54.78, Δ = 24°28’, and D = 5°30’, compute the deflections…

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Q: It is necessary to lay out the center line of a proposed road construction along Macapagal Avenue.…

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Q: The bearing of the tangents of a simple curve are N75°12'E and S78°36'E respectively. 3. What is the…

A: We have to find the value of degree of the curve using chord basis.

Q: A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of 180°…

A: Given:- I=Angle of intersection=230o-1800Degree of curve=4oRadius=17194=429.5 m

Q: Surveying

A: Usibg relation :L=NS22H1+H2H1=eye level=1.5mH2=asphalt level=0

Q: A 3% ascending grade meets a descending grade at the vertex at sta. 20+100 and at elevation 120 m.…

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Q: T2 B. Figure 10.7 Example: Given: 28 + 63-2 (figure 10,7). Determine tangent length, curve length,…

A: Radius(R)=1000 ft β=75°

Q: The simple curve has a deflection angle of 105 degrees and 15 minutes and the length of its tangent…

A: To determine stationing of station PC.

Q: STATION NORTHINGS 0+000 11475.55 PI1 11478.80 11179.37 P12 P13 10804.76 P14 10512.37 V1 11245.48 V2…

A: Length of a chord is 132.24 mDegree of curve = 8 degreesDeflection angle = 15028'To DetermineTable…

Control Survey and Geodetic reductions

Control surveys or survey controls are used to establish reference points as a basis for various construction activities. Vertical and horizontal control points are to be established in a control survey to increase accuracy. After establishing the control points, all other types of surveys such as topographic, right-of-way, aerial mapping, construction layout, boundary surveys, and utility mapping can be worked upon so that control networks can be formed. The place from which the observations are made is called a survey station.