number 3. PC1PI10+000LctPT1R111STATION NORTHINGSEASTINGS0+00011475.558927.24PC29291.919546.66PI111478.80P1211179.37R2V1PI310804.769282.44Lc2PI410512.379433.481312PCCV111245.489490.41PI2V211074.509472.69END10203.859016.99Lc3R3V2LINEAZIMUTHDISTANCE0-PI1PI1-V1V1-V2PT2V2-PI3PI3-PI4PI4-ENDPC3R4CURVELC1+140PI31stCurve2nd Curve14Lc43rd Curve4th Curve5th CurvePRCSTATIONING15PCPTLc5PC2P14PCCR5PT2PC3PRCPT3PT3ENDEND OF ROAD---- ---- Shown on the drawing are the application of the different horizontal curves for aroadway project.GIVEN:Coordinates of Intersecting PointsLength of Chord of the First Simple is 132.24 mDegree of Curve of the first curve of the compound Curve is 8 degreesThe deflection angle from PC3 to Sta. 1+140 is 15°28'REQUIRED:1. The azimuth and distance of the tangent lines.2. The Intersecting Angle (1), radius (R), tangent distance (T), Length of Curve (Lc) ofall the curves3. The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of ProjectFill up your answer on the given table.Show solutions.IFICEVESITY

To Determine Table 3 ( The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of Project)…

PC1 PI1 0+000 Lct PT1 R1 11 STATION NORTHINGS EASTINGS 0+000 11475.55 8927.24 PC2 9291.91 9546.66 PI1 11478.80 P12 11179.37 R2 V1 PI3 10804.76 9282.44 Lc2 PI4 10512.37 9433.48 13 12 PCC V1 11245.48 9490.41 PI2 V2 11074.50 9472.69 END 10203.85 9016.99 Lc3 R3 V2 LINE AZIMUTH DISTANCE 0-PI1 PI1-V1 V1-V2 PT2 V2-PI3 PI3-PI4 PI4-END PC3 R4 CURVE LC 1+140 PI3 1stCurve 2nd Curve 14 Lc4 3rd Curve 4th Curve 5th Curve PRC STATIONING 15 PC PT Lc5 PC2 P14 PCC R5 PT2 PC3 PRC PT3 PT3 END END OF ROAD ---- ----

PC1 PI1 0+000 Lct PT1 R1 11 STATION NORTHINGS EASTINGS 0+000 11475.55 8927.24 PC2 9291.91 9546.66 PI1 11478.80 P12 11179.37 R2 V1 PI3 10804.76 9282.44 Lc2 PI4 10512.37 9433.48 13 12 PCC V1 11245.48 9490.41 PI2 V2 11074.50 9472.69 END 10203.85 9016.99 Lc3 R3 V2 LINE AZIMUTH DISTANCE 0-PI1 PI1-V1 V1-V2 PT2 V2-PI3 PI3-PI4 PI4-END PC3 R4 CURVE LC 1+140 PI3 1stCurve 2nd Curve 14 Lc4 3rd Curve 4th Curve 5th Curve PRC STATIONING 15 PC PT Lc5 PC2 P14 PCC R5 PT2 PC3 PRC PT3 PT3 END END OF ROAD ---- ----

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

number 3.

PC1
PI1
0+000
Lct
PT1
R1
11
STATION NORTHINGS
EASTINGS
0+000
11475.55
8927.24
PC2
9291.91
9546.66
PI1
11478.80
P12
11179.37
R2
V1
PI3
10804.76
9282.44
Lc2
PI4
10512.37
9433.48
13
12
PCC
V1
11245.48
9490.41
PI2
V2
11074.50
9472.69
END
10203.85
9016.99
Lc3
R3
V2
LINE
AZIMUTH
DISTANCE
0-PI1
PI1-V1
V1-V2
PT2
V2-PI3
PI3-PI4
PI4-END
PC3
R4
CURVE
LC
1+140
PI3
1stCurve
2nd Curve
14
Lc4
3rd Curve
4th Curve
5th Curve
PRC
STATIONING
15
PC
PT
Lc5
PC2
P14
PCC
R5
PT2
PC3
PRC
PT3
PT3
END
END OF ROAD
---- ----

Shown on the drawing are the application of the different horizontal curves for a
roadway project.
GIVEN:
Coordinates of Intersecting Points
Length of Chord of the First Simple is 132.24 m
Degree of Curve of the first curve of the compound Curve is 8 degrees
The deflection angle from PC3 to Sta. 1+140 is 15°28'
REQUIRED:
1. The azimuth and distance of the tangent lines.
2. The Intersecting Angle (1), radius (R), tangent distance (T), Length of Curve (Lc) of
all the curves
3. The Stationing of PC, PT, PC2, PCC, PT2, PC3, PRC, PT3 and End of Project
Fill up your answer on the given table.
Show solutions.
IFICE
VESITY

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