Part A Compute the stopping sight distance available given a 520-ft curve, grades of 91 = +2.00% and 92 = -2.50%, VPI at station 96 + 80, and elevation 845.26 ft, stakeout at full stations. Assume h₁ = 3.50 ft. and h₂ = 2.00 ft. Express your answer in feet to five significant figures. S = ΜΕ ΑΣΦ vec Submit Request Answer ? ft

Q: A-2.40% grade meets a +1.50% grade at station 44+25 and elevation 3386.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.5% The station of point of…

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: Compute the passing sight distance available given a 435-ft curve, grades of g₁=+2.00% and 92 =…

A: Curve length, L = 435 fth1 = 3.25 fth2 = 4.50 ftg1 = 2 %g2 = -1.5 %VPI at station 96+80Elevation =…

Q: Q1/A horizontal curve with degree of curvature of 4° and intersection angle of 55°25', the PC is…

A: A curve is given between two stations with the following observations.degree of curve, D=…

Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: Compute the passing sight distance available given a 440-ft curve, grades of g₁ = +2.00% and 9₂…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: Compute the passing sight distance available given a 475-ft curve, grades of g1=+2.00% and…

A: Answer:To compute the passing sight distance, we need to analyze the given information…

Q: A spiral is to be introduced to a 4-lane highway with a 2° 30' horizontal curve, maximum…

A: A curve, without sharp turns is a continuous and smooth line. The radius of curvature of the normal…

Q: Given a transition curve length of 85.500m, a design radius of 620.000m, a deflection angle of 95…

A: GIVEN DATA, Length of the  transition curve (l)= 85.5m design radius of the curve (R) = 620 m…

Q: Part A For D = 1600 ft and R=550 ft, compute R₂ to fit the requirements of the figure and make the…

A: D = 1600 ft R = 550 ftTo find:Rx

Q: A vertical curve on a roadway has a BVC at station 23+00 and an elevation of 900.00'. If the EVC is…

A: Given data: BVC station=23+00 EVC station=33+00 g1=4.00% g2=-3.50% Elev at station 29+00=?

Q: Item 2 Grades of g₁ = -2.50% and 92 = +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 856 ftat 20+50 and y= 860 ft

Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

A:

Q: A -1.10% grade meets a +0.60% grade at station 36+00 and elevation 800.00 ft. The +0.60 grade then…

A: Grade, g1 = +2.40Grade, g2 = +0.60Elevation = 800.00 ft

Q: A 500-ft curve, g₁ = -2.00%, 92 = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A:

Q: Compute the passing sight distance available given a 440-ft curve, grades of ₁₂ Express your answer…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: as of ₁-2.50% and 9₂ +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a foxed elevation…

A: g1= -2.50% g2= + 1.50% PVI Elevation = 856 ft at 20+50 and y= 860 ft

Q: 2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout…

A: The elevations and grades at the beginning and end of the curve need to be determined. We will call…

Q: elevation 854.00 ft at station 20 + 50. Field conditions require a highway curve to pass through a…

A:

Q: Field conditions require a highway curve to pass through a fixed point. Compute a suitable…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 868 ft and station = 22+00Fixed elevation, y = 872 ft and…

Q: Grades of g₁ = -2.50% and 92 = +1.50%, VPI elevation 860.00 ft at station 22 +00, and a fixed…

A: To solve this problem, we need to calculate the elevations of an equal-tangent vertical curve given…