Compute the passing sight distance available given a 440-ft curve, grades of ₁₂ Express your answer in feet to five significant figures. VT ΑΣΦ S= 6 ⒸI ? ft +2.00% and 92 -1.50%. VPI at station 96+80, and elevation 845.26 ft, stakeout at full stations. (Assume h₁ = 3.75 ft and h₂=4.75 ft.)

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: Determine the P.C. and P.T. for the horizontal curve using the following information:…

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Q: Compute the passing sight distance available given a 440-ft curve, grades of g₁ = +2.00% and 9₂…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: QUESTION 3 A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110…

A:

Q: Compute the passing sight distance available given a 475-ft curve, grades of g1=+2.00% and…

A: Answer:To compute the passing sight distance, we need to analyze the given information…

Q: Given a transition curve length of 85.500m, a design radius of 620.000m, a deflection angle of 95…

A: GIVEN DATA, Length of the  transition curve (l)= 85.5m design radius of the curve (R) = 620 m…

Q: A 500-ft curve, grades of g₁ = +1.50 % and g₂ = -2.50%, VPI at station 96 + 80 and elevation 841.26…

A: The initial grade of the curve = 1.5%The final grade of the curve = -2.50%The station of point of…

Q: Vertical Curve 4.) The same section of road is also on a vertical curve. Where L= 200 G1 = 2% and G2…

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Q: A 500-ft curve, 91 = -2.00%, g2 = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500 ftPVI elevation = 5388.26 ftPVI station = 98+10

Q: Given: L = 20 stations, G1=-2%,G2=+1%; The elevation difference from the PC to the low point of the…

A: The Elevation difference from PC to low point of curve is given by ; X X = g1 LA where ; g1 = -2 % L…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects…

A: We have to find station and elevation of the PVC and the PVI according to the given data like speed…

Q: Compute the stopping sight distance available given a 490-ft curve, grades of g₁ = +2.00% and 9₂ =…

A:

Q: A horizontal curve is shown in the figure below. There is a point P on the circular curve. Given:…

A: Horizontal curve  A horizontal curve connects two tangent strips of road, allowing a vehicle to make…

Q: 2. Vertical Curve Given the following vertical curve data, compute the elevations of the curve,…

A: Given: Given the following vertical curve data             g1= -1%, g2 = 1.5%, L=100m, PVI at 2+200,…

Q: Determine variables requested below for a horizontal curve with the following characteristics.…

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Q: A +2% gradient and -3% gradient intersect at a VPI with chainage 800.000m and elevation above datum…

A: Gradient 1, Gradient 2, Vertical point of intersection with chainage R.L of VPI Length of the…

Control Survey and Geodetic reductions

Control surveys or survey controls are used to establish reference points as a basis for various construction activities. Vertical and horizontal control points are to be established in a control survey to increase accuracy. After establishing the control points, all other types of surveys such as topographic, right-of-way, aerial mapping, construction layout, boundary surveys, and utility mapping can be worked upon so that control networks can be formed. The place from which the observations are made is called a survey station.