2. Vertical Curve Given the following vertical curve data, compute the elevations of the curve, including low/high point, and even 20m stations. Use either Tangent Offset or General Equation method. PVI @ 2+200 g1=-1% L=100m PVI EI.=560.000 g2=1.5%

Q: A grade line having a slope of 5% intersect another grade line BC having a slope of -3% at vertex…

A: Given Data: g1=5%g2=-3%PC=95mPT=97 mLength of curve=200 mIt is asked to find elevation at quarter…

Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

A:

Q: 3. Two tangents intersect at chainages 50.60 (50 chains and 60 links), the deflection angle being…

A:

Q: A 500-ft curve, 91 = -2.00%, g2 = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500 ftPVI elevation = 5388.26 ftPVI station = 98+10

Q: A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: Given data: Elevation of PVC Station of PVC PVT station

Q: 25. For a preliminary vertical alignment of a roadway, the straight tangent sections are established…

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Q: You have designed a 500 ft long simple horizontal curve that has an intersection angle of 45…

A:

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