Choose the correct answer for the following que The equivalent E form of the confidence interval 0.55
Choose the correct answer for the following que The equivalent E form of the confidence interval 0.55
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![| j - E <p< p +E where
Examus
- cdn.student.uae.examus.net/?ridban=1&sessi...
1.
STAT-101 FEX_2021_2_Male
17 - 30
116:06
Choose the correct answer for the following question:
62d
ce
ce362d
The equivalent
form of the confidence interval 0.55 <p <0.85 is equal
Edcf7
Formulae Sheet STAT-101-2
d.f. = min (n, – 1,n2 – 1)
ef917
Residual = observed y – predicted y
-E<µ< +E where E =
Za/2· Jr
62dcf917
-
p - E<p < p + E where E =,
Point estimate =
U.C.L.+ L.C.L
nExy-(Ex)(Ey)
n Ex²-Ex)²/nEy²-(Ey)²
The regression equation ŷ = bo + bịx,
pq
Margin of Error, E =
upper C.L.-lower C.L.
72
n =
12
Za/2
ī- E<µ <ã +E where E = ta,.
bo = ỹ – bịā
Xi+x2
E
n+nz
n(Exy)-(Ex)Ey)
nEx²)-Ex)²
Slope, b1
%3D
y-intercept, b,
||
b, =r
ポー!
t =
F
%3D
nΣx3)-Σx) 2
F 3=
t = (X, – X,)/ si +
0.70 ± 0.20
V n1
t =
a.
n2
ce362 917
MacBook Pro
ce36zdcf917
6)
P
K]
个](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50722bca-d689-4ae1-8446-78c9154032e6%2F52704c77-fd53-40d0-92cd-22e139dca584%2F5qm2vw9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:| j - E <p< p +E where
Examus
- cdn.student.uae.examus.net/?ridban=1&sessi...
1.
STAT-101 FEX_2021_2_Male
17 - 30
116:06
Choose the correct answer for the following question:
62d
ce
ce362d
The equivalent
form of the confidence interval 0.55 <p <0.85 is equal
Edcf7
Formulae Sheet STAT-101-2
d.f. = min (n, – 1,n2 – 1)
ef917
Residual = observed y – predicted y
-E<µ< +E where E =
Za/2· Jr
62dcf917
-
p - E<p < p + E where E =,
Point estimate =
U.C.L.+ L.C.L
nExy-(Ex)(Ey)
n Ex²-Ex)²/nEy²-(Ey)²
The regression equation ŷ = bo + bịx,
pq
Margin of Error, E =
upper C.L.-lower C.L.
72
n =
12
Za/2
ī- E<µ <ã +E where E = ta,.
bo = ỹ – bịā
Xi+x2
E
n+nz
n(Exy)-(Ex)Ey)
nEx²)-Ex)²
Slope, b1
%3D
y-intercept, b,
||
b, =r
ポー!
t =
F
%3D
nΣx3)-Σx) 2
F 3=
t = (X, – X,)/ si +
0.70 ± 0.20
V n1
t =
a.
n2
ce362 917
MacBook Pro
ce36zdcf917
6)
P
K]
个
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