A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 181 students using Method 1 produces a testing 1. average of 88.9. A sample of 197 students using Method 2 produces a testing average of 63.9. Assume that the population standard deviation for Method 1 is 15.73, while the population standard deviation for Method 2 is 17.35. Determine the 98% Method 1 and students using Method 2. Step 1. Find the critical value that should be used in constructing the confidence interval. confidence interval for the true difference between testing averages for students using Answer: *- 88.9 1.73 181 n2 = 197 x, 63.9 6- 15.73 Puake 0.9901 2 = 17, 35 Step 2. Construct the 98% confidence interval. Round your answers to one decimal %3D place. Answer: Lower endpoint: Upper endpoint:

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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average of A of 197 using 2 a average
confidence for true for using
of that the for 1 is while
A the of two for
ER 11) (2 points each)
DUE DATE: WEEK OF MAY 3, 2021
1.
average
Method 1 and students using Method 2.
Step 1. Find the critical value that should be used in constructing the confidence
interval.
x= 88.9 - 15.73
%3D
181=4
X, 63.9
o2= 17, 35
Answer:
nz =197
%3D
Pucke 0.9901
()
Step 2. Construct the 98% confidence interval. Round your answers to one decimal
place.
Answer: Lower endpoint:
Upper endpoint:
An investigator compares the durability of two different compounds used in the
manufacture of a certain automobile brake lining. A sample of 240 brakes using
Compound 1 yields an average brake life of 42,783 miles. A sample of 230 brakes
Compound 2 yields an average brake life of 40,727 miles. Assume that the populat
standard deviation for Compound 1 is 1639 miles, while the population standard
deviation for Compound 2 is 4130 miles. Determine the 80% confidence interval
the true difference between average lifetimes for brakes using Compound 1 and br
2.
using Compound 2.
n,-240 x- 42,783 0 1639
%3D
Mz=230 X2=40,727 0,=4130
Step 1. Find the critical value that should be used in constructing the confidence
interval.
Answer:
42,783-40,727
1
2.
4130
246
230
Transcribed Image Text:average of A of 197 using 2 a average confidence for true for using of that the for 1 is while A the of two for ER 11) (2 points each) DUE DATE: WEEK OF MAY 3, 2021 1. average Method 1 and students using Method 2. Step 1. Find the critical value that should be used in constructing the confidence interval. x= 88.9 - 15.73 %3D 181=4 X, 63.9 o2= 17, 35 Answer: nz =197 %3D Pucke 0.9901 () Step 2. Construct the 98% confidence interval. Round your answers to one decimal place. Answer: Lower endpoint: Upper endpoint: An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 240 brakes using Compound 1 yields an average brake life of 42,783 miles. A sample of 230 brakes Compound 2 yields an average brake life of 40,727 miles. Assume that the populat standard deviation for Compound 1 is 1639 miles, while the population standard deviation for Compound 2 is 4130 miles. Determine the 80% confidence interval the true difference between average lifetimes for brakes using Compound 1 and br 2. using Compound 2. n,-240 x- 42,783 0 1639 %3D Mz=230 X2=40,727 0,=4130 Step 1. Find the critical value that should be used in constructing the confidence interval. Answer: 42,783-40,727 1 2. 4130 246 230
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