A method produces nanoparticles of various sizes.The diameters of a sample of 60 nanoparticles produced by this methodare measured to be 26.3 + 4.5nmBased on this sample, the 96.5% confidence interval for the meandiameter of nanoparticles produced by this method is calculated as:SoSample mean (zg x o)The samplemean isand o is***Use only 1 decimal place for answers for example if you get 20.396,use 20.4

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Answered: A method produces nanoparticles of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The melting points of two alloys used in formulating solder were investigated by melting 21 samples of each material. The sample mean and standard deviation for alloy 1 was īi = 420°F and si = T2 = 426°F and s2 = 3°F. Find a 95% confidence interval on the difference in 4°F , and for alloy 2, they were %3D the two means. (-0.061, 0.861) -4.119, 15.129) (-8.205, –3.795) (1.857, 18.943)
Sand is packed into bags which are then weighed on scales. It is known that if full bags of sand are intended to weigh u kg, then the weight recorded by the scales will be normally distributed with a mean u kg and a standard devlation of 0.36 kg. How many times would a full sack have to be weighed so that the estimate of the weight would be within 0.2 kg of the true weight with 99.5% confidence? Select one: O a 45 Ob. 56 OC 26 Od. The corect answer is not listed O e 85
Hanna got the following R output from gary the statistician: data: dati and dat2 t = 3.8074, df = 9, p-value = 0.00417 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0.7940126 3.1187708 sample estimates: mean of the differences 1.956392 She knows that gary was analyzing data from a study in which 10 persons participated. What kind of hypothesis testing was Gunnar performing? 1. Hypothesis tests for differences in the means of two independent pop- ulations. 2. Hypothesis test for the variance of two independent populations. 3. Hypothesis test for paired measurements. 4. Hypothesis test for the mean of one population. 5. R-command:
A sample of size 65 with =71.9 and s = 16.6 is used to estimate a population mean µ. Find the 90% confidence interval for u. Round the answers to one deicimal. Question Help: Written Example Submit Question hp -> Ce & 96 %24
We want to estimate the mean number of pages per book in the fiction section of the large school library at a 99% confidence level. A sample of 35 fiction books is randomly selected, and the mean number of pages is calculated to be 291.8 pages per book with a standard deviation of 47.6 pages per book. Use the table to find the appropriate value of t* to use in the given scenario. Enter in the value of t* exactly as you see it written in the table. 1.684 1.697 2.704 2.750
A sample of size n=45 has sample mean x =56.9 and sample standard deviation s=9.4. Part: 0/2 Part 1 of 2 Construct a 99% confidence interval for the population mean u. Reund the answers to ene decimal place. A 99% confidence interval for the population mean is
A sample of 20 items provides a sample standard deviation of 4.
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
A random Sample of 55 students has a text score with x̄ =78.5 Assume the population standard deviation is 9.8. Construct a 90% confidence interval for the population mean, µ
A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows. Hours of Training 1 4 7 3 2 2 5 5 1 6 Defects per Countertop 5 1 0 3 5 4 1 2 8 2
Suppose we are able to use a normal model. In order to construct a 99% Confidence Interval, we have to find the margin of error (ME), and we can use the following formula: 2.579*SE, where SE is computed with the image that's attached to this problem. Using SE = 0.049, find ME for the 99% Confidence Interval. Round your answer to 3 decimal places.
Joshua wants to replicate a study where the lowest observed value is 12.4 while the highest is 12.8. He wants to estimate the population mean u to within an error of 0.025 of its true value. Using 99% confidence level, find the sample size n that he needs. Solution: (a) Known Information: Za/2 ;E = (b) Desired Sample Size

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